Question

20-x2/y-x for x=2 and y=6

Answer 1

$\text{Hello there!}\\\\\text{Plug in the numbers and solve:}\\\\\frac{20-x^2}{y-x}\\\\\frac{20-2^2}{6-2}\\\\\frac{20-4}{6-2}\\\\\frac{16}{4}\\\\=4\\\\\boxed{\text{Answer: 4}}$

Answer 2

Use substitution to solve the equation:
20-4/4.
4/4=1 so it simplifies to 20-1 which equals 19