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Tresset [83]
2 years ago
9

The 17th term of an Arithmetic sequence is 51. If the commons difference is 7, what is the first term ?

Mathematics
1 answer:
vovikov84 [41]2 years ago
8 0

Answer:

The first term is:

  • a_1=-61

Step-by-step explanation:

The arithmetic sequence is defined by

a_n=a_1+\left(n-1\right)d

where

a_1 is the first term

d is the common difference

as

the 17th term of an arithmetic sequence is 51.

i.e. a_{17}=51

so

a_n=a_1+\left(n-1\right)d

a_{17}=a_1+\left(17-1\right)d        

51=a_1+\left(17-1\right)7         ∵ n = 17, a_{17}=51 , d=7

a_1+112=51                   ∵ \left(17-1\right)\cdot \:\:7=112

a_1=-61

Therefore, the first term is:

  • a_1=-61
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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that \mu = 74, \sigma = 15

Question a:

Sample of 36 means that n = 36, s = \frac{15}{\sqrt{36}} = 2.5

This probability is 1 subtracted by the pvalue of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{78 - 74}{2.5}

Z = 1.6

Z = 1.6 has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that n = 150, s = \frac{15}{\sqrt{150}} = 1.2247

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

Z = \frac{X - \mu}{s}

Z = \frac{77 - 74}{1.2274}

Z = 2.45

Z = 2.45 has a pvalue of 0.9929

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Z = \frac{X - \mu}{s}

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Z = -2.45

Z = -2.45 has a pvalue of 0.0071

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Sample size of 219 means that n = 219, s = \frac{15}{\sqrt{219}} = 1.0136

This probability is the pvalue of Z when X = 74.2. So

Z = \frac{X - \mu}{s}

Z = \frac{74.2 - 74}{1.0136}

Z = 0.2

Z = 0.2 has a pvalue of 0.5793

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