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Tresset [83]
3 years ago
9

The 17th term of an Arithmetic sequence is 51. If the commons difference is 7, what is the first term ?

Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

The first term is:

  • a_1=-61

Step-by-step explanation:

The arithmetic sequence is defined by

a_n=a_1+\left(n-1\right)d

where

a_1 is the first term

d is the common difference

as

the 17th term of an arithmetic sequence is 51.

i.e. a_{17}=51

so

a_n=a_1+\left(n-1\right)d

a_{17}=a_1+\left(17-1\right)d        

51=a_1+\left(17-1\right)7         ∵ n = 17, a_{17}=51 , d=7

a_1+112=51                   ∵ \left(17-1\right)\cdot \:\:7=112

a_1=-61

Therefore, the first term is:

  • a_1=-61
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Natali [406]

Answer:

254.5 cm²

Step-by-step explanation:

area = πr²

area = 3.14159 × (9 cm)²

area = 254.5 cm²

4 0
2 years ago
Find sec theta if theta is in quadrant 4 and sin theta= -1/5
lara31 [8.8K]

Answer:

\frac{5}{2\sqrt{6} }

Step-by-step explanation:

Since Θ is in fourth quadrant then cosΘ > 0, as is secΘ

Given

sinΘ = - \frac{1}{5}, then

cosΘ = \sqrt{1-(-1/5)^2}

         = \sqrt{1-\frac{1}{25} } = \sqrt{\frac{24}{25} } = \frac{2\sqrt{6} }{5}

Hence

secΘ = \frac{1}{\frac{2\sqrt{6} }{5} } = \frac{5}{2\sqrt{6} }

5 0
3 years ago
Read 2 more answers
5) Find the value of the term in the arithmetic sequence. (an = a1 + (n - 1)d) 11,
kvasek [131]

Answer:

139, I am sorry if I'm wrong

Step-by-step explanation:

a1=11; d=19-11=8

a17=11+(17-1)*8=11+128=139

6 0
3 years ago
Need help please! Will give it to the brainliest. Which expression models the bacterium's volume? Picture is below.
Tomtit [17]

The expression C. \pi (1)^{2} (0.5) cubic \mu \mathrm{m} represents the bacterium's volume.

Step-by-step explanation:

Step 1:

The E. Coli bacterium is in the shape of a cylinder.

The volume of a cylinder is given by multiplying π with the square of the radius (r²) and the height of the cylinder.

The volume of a cylinder, V=\pi r^{2} h.

In the given diagram, E. Coli has a radius of 1 \mu \mathrm{m} and a height of 0.5 \mu \mathrm{m}.

Step 2:

By substituting the values in the equation, we get

The volume of the E. Coli bacterium = \pi (1)^{2} (0.5) cubic \mu \mathrm{m}.

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7 0
4 years ago
Please help me with this.
tatyana61 [14]

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

<h3>How to evaluate a piecewise function at given values</h3>

In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:

<h3>r(- 3): </h3>

-3 ∈ (- ∞, -1]

r(- 3) = - 2 · (- 3) + 9

r (- 3) = 15

<h3>r(- 1):</h3>

-1 ∈ (- ∞, -1]

r(- 1) = - 2 · (- 1) + 9

r (- 1) = 11

<h3>r(1):</h3>

1 ∈ (-1, 5)

r(1) = 2 · 1² - 4 · 1 - 5

r (1) = - 7

<h3>r(5):</h3>

5 ∈ [5, + ∞)

r(5) = 4 · 5 - 7

r (5) = 13

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

7 0
2 years ago
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