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2 years ago

To get from point A to point B you must avoid walking

Mathematics

1 answer:

Nikitich [7]2 years ago

7 0

the rigth awnser is 41 meaters east to were

Step-by-step explanation:

possible to walk through the

You might be interested in

4x + 3y = 1<br> x - 3y = -11

JulijaS [17]

Answer:

(- 2, 3 )

Step-by-step explanation:

Given the 2 equations

4x + 3y = 1 → (1)

x - 3y = - 11 → (2)

Adding the 2 equations term by term will eliminate the y- term

5x + 0 = - 10

5x = - 10 ( divide both sides by 5 )

x = - 2

Substitute x = - 2 into either of the 2 equations and solve for y

Substituting into (1)

4(- 2) + 3y = 1

- 8 + 3y = 1 ( add 8 to both sides )

3y = 9 ( divide both sides by 3 )

y = 3

solution is (2, - 3 )

4 0

3 years ago

Read 2 more answers

Is 0.56 greater or less than 4/5

aliina [53]

Answer:

0.56 is less than 4/5

Step-by-step explanation:

Could I get brainliest please?

3 0

2 years ago

Read 2 more answers

A angles of an equilateral triangle are congruent. If x represents the measure of the third angle of the triangle, what is x?

Tatiana [17]

Answer:

Step-by-step explanation:

Since x is the measure of the third angle and all 3 angles are congruent then

All 3 angles have a measure of x

The sum of the 3 angles in a triangle = 180°, this

x + x + x = 180 ← is the required equation

3x = 180 ( divide both sides by 3 )

x = 60

8 0

2 years ago

Suppose that a company has recently started manufacturing a new line of helicopters, and it took 106.496 labor days to complete

Allisa [31]

A "learning rate" expresses the ratio of the labor spent on the n-th item to that spent on the (n/2)-th item. That is, the 8th helicopter manufactured took days related by ...

0.8 × (days for 8th) = (days for 16th)

(days for 8th) = (days for 16th)/0.8 = 1.25×(days for 16th)

Then the days for the 4th are 1.25 times that, and the days for the 2nd are 1.25 times the days for the 4th. The days for the first helicopter will be

... 1.25⁴×106.496 days = 260 days

The appropriate choice is

... d. 260

5 0

2 years ago

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago