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ivolga24 [154]
2 years ago
10

Which graph represents an exponential function?

Mathematics
1 answer:
Brut [27]2 years ago
3 0
The first one. It is called an exponential decay curve.
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What is the ratio unknown amount (x) invested in company A to the know amount ($24) invested in company B? Write the answer as a
lara [203]

Answer:

X/24

Step-by-step explanation:

he ratio of the unknown amount (x) invested in company A to the known amount ($24) invested in company B is X/24

7 0
3 years ago
???????I don't get it
Marta_Voda [28]
To fill the squares look for the one filled in column/row/diagonal and figure out its sum.
All other columns/rows/diagonals must be equal to that, so whenever there is a column/row/diagonal with a single missing value you can add the others up and calculate the missing value.
So you have to find those single missing value columns/rows/diagonals, fill them out and continue with the next one until the whole square is filled in.


8 0
3 years ago
Judy took $30 with her to spend on popcorn and drinks for her and her friend At the movies popcorn was $5 the price of each soda
Sonbull [250]
So 2 popcorn = $5×2= $10
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6 0
2 years ago
How many points are collinear with points Cand D?
asambeis [7]

Answer: B) one

This one point is point U since it is on line segment CD. In contrast, a point like point E is not on line CD, so E is not collinear with C and D.

3 0
3 years ago
Select the two values of x that are roots of this equation 3x^2 + 1 =5x
Zina [86]

Answer:

x = 1.434 and x=0.232

Step-by-step explanation:

To find the root of the equation stated above we need to:

(1) Write the polynomial equation with zero on the right hand side:

3x^{2} + 1 = 5x ⇒ 3x^{2} -5x + 1 = 0

(2) Divide the whole equation by 3

3x^{2} -5x + 1 = 0 ⇒ x^{2} -\frac{5}{3}x + \frac{1}{3}= 0

(3) Use the quadratic formula to solve the quadratic equation:

The quadratic formula states that the two solutions for a quadratic equation is given by:

\frac{-b±\sqrt{b^{2} - 4ac}}{2a} (1)

In this case, a = 1, b = -\frac{5}{3}, c= \frac{1}{3}

Substituiting a, b and c in equation (1) We get:

\frac{-\frac{5}{3}±\sqrt{(-\frac{5}{3})^{2} - 4(1)(\frac{1}{3})}}{2(1)} (1)

The two solutions are:

x = 1.434 and x=0.232

8 0
2 years ago
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