Fill in the missing number: 497 + = 1,404
2 answers:
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The stem-and-leaf plot for 29,22,21,6,13,6,17,29,26,9,16,10,25,3,2,23,13,10,7,16,29,30,4,11,7,28,27,22,10 is shown in the image attached below (see attachment).
<h3>What is a Stem-and-leaf Plot?</h3>A stem-and-leaf plot is a table which is used to display a set of data in such a way that, on the left we have the "stem" which displays the first digit or digits of a data value.
On the right, we have the 'leaf' which displays the last digit of the data value.
For example, if we are to represent "25" and "26" on a stem-and-leaf plot, we would have: 2 | 5, 6.
Therefore, the stem-and-leaf plot for 29,22,21,6,13,6,17,29,26,9,16,10,25,3,2,23,13,10,7,16,29,30,4,11,7,28,27,22,10 is shown in the image attached below (see attachment).
Learn more about the stem-and-leaf plot on:
Answer:
Slope of the base segment line is zero, hence base segment is horizontal
Slope of the segment that joins the vertex angle to the midpoint of its base is undefined hence the line is vertical
Therefore, angle between base segment line and the segment line from the vertex angle to the midpoint is perpendicular
Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base
Step-by-step explanation:
Here we prove the required relation as follows;
Let the isosceles be ABC
The coordinates of the points are
C = (0, 0) (Vertex)
A = (-a, b)
C = (a, b)
P = (0, b) (Midpoint of base)
Therefore, the gradient or slope of the base AC is presented as follows;
Hence, segment AC is vertical
Hence, segment CP is vertical
Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base.