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Natalka [10]
3 years ago
5

Understand how to apply the equations for 1-dimensional motion to the y and x directions separately in order to derive standard

formulae for the range and height of a projectile.
Physics
1 answer:
dexar [7]3 years ago
8 0

Answer:

the equations of motion can be separated into an equation that depends on a single variable.

Explanation:

he one-dimensional kinematics equations can be applied to two-dimensional systems because we can write the equations in such a way that each one of them depends on variables in a single dimension plus time, which, because it is a scalar, can be used in all dimensions.

A mathematical way of saying this is that the equations of motion can be separated into an equation that depends on a single variable.

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At the time of the founding of the country, most Americans worked as
STatiana [176]

Answer:

Farmers

Explanation:

At the time of founding our country most soldiers in the revolutionary war were farmers who were inexperienced.

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3 years ago
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A block weighing 10 newtons is resting on a plane inclined 30° to the horizontal. What is the magnitude of the normal force acti
aleksley [76]

Magnitude of normal force acting on the block is 7 N

Explanation:

10N = 1.02kg

Mass of the block = m = 1.02 kg

Angle of incline Θ =  30°

Normal force acting on the block = N

From the free body diagram,

N = mgCos Θ

N = (1.02)(9.81)Cos(30)

N = 8.66 N

Rounding off to nearest whole number,

N = 7 N

Magnitude of normal force acting on the block = 7 N

7 0
3 years ago
Why do plants produce their own food
Serhud [2]

Because way back, when there were some kinds of plants that made
their own food, and other kinds of plants that depended on dinosaurs or
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7 0
4 years ago
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The second-order rate constants for the reaction of oxygen atoms ·with aromatic hydrocarbons have been measured (R. Atkinson and
Blizzard [7]

Answer:  Frequency factor  A = 8 × 10⁹

activation energy Ea = 15.5 KJ/Mol

Explanation: to begin, let us first define the parameters given;

K₁ = 1.44 × 10⁷dm³mol⁻¹s⁻¹

K₂ = 3.03 × 10⁷ dm³mol⁻¹s⁻¹

K₃ = 6.9 × 10 dm³mol⁻¹s⁻¹

also T₁ = 300.3 K

T₂ = 341.2 K

T₃ = 392.2 K

we know that;

㏑ K₂ / K₁ = Ea/R [1/T₁ -1/T₂]

where R is given as 8.314 J/mol-k

Ea = activation energy

K₁, K₂ = rate constant

T₁, T₂ = Temperature

therefore, ㏑ (3.03 × 10⁷/ 1.44 × 10⁷) = Ea / 8.314 [1/300.3 - 1/341.2]

this gives Ea = 15496.16 J/Mol ≈ 15.5 KJ /Mol

∴ Ea = 15.5 KJ/ Mol

also given that K = A e⁻∧Ea/RT

here A = frequency factor

∴ 6.9 × 10⁷ = A e⁻ ∧(15496.16/8.314 × 392.2)

A = 7.99 × 10⁹ = 8 × 10⁹

3 0
3 years ago
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Lapatulllka [165]
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