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Alexxx [7]
3 years ago
6

Solar energy technology is expensive, but it has been improving in efficiency over the years. Today, many small appliances, such

as calculators, watches, and patio lights, are powered with solar panels. How does this increased use of solar energy affect the availability of solar energy?
Physics
1 answer:
zvonat [6]3 years ago
5 0
Solar energy is kind of like a natural waterfall.

The amount of water you catch in your bucket at the bottom of the falls
has no affect whatsoever on how much pours over the falls.

It doesn't matter how much solar energy we use ... to run our calculators
and patio lights, or to run every car and industrial manufacturing plant
in the world ... it has no effect whatsoever on the amount of solar energy
reaching Earth from the sun and available to us.

IN FACT . . . if we ever reach the point of using humongous amounts of
solar energy, that may make solar energy a little bit MORE available to us.
It'll mean that we're using less coal, oil, and gas, belching less pollution
into the atmosphere, making the air a little more clear and transparent,
so a little MORE solar energy reaches the ground where we can collect it. 
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Answer:

it’s 2.5 m/s

Explanation:

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6 0
3 years ago
A cylindrical tungsten filament 16.0 cm long with a diameter of 1.00 mm is to be used in a machine for which the temperature wil
KonstantinChe [14]

Answer:

Explanation:

Resistance of the tungsten wire

R = resistivity x length / cross sectional area

= \frac{5.25\times10^{-8}\times16\times10^{-2}}{3.14\times(.5\times10^{-3})^2}

= 107 x 10⁻⁴ ohm

Resistance at 120 degree can be obtained from the following formula

R_t = R_0( 1 + \alpha\times t )

R_t = 107\times10^{-4}( 1 + .0045\times 100)

= 155.15 x 10⁻⁴ ohm

= 160 x 10⁻⁴ ohm ( rounding off to two syg fig )

current = 12.5

potential diff = 12.5 x 155.15 x 10⁻⁴ V

=  0 .1939 V

= .19 V

required electric field = potential diff / length of wire

= .1939 / 16 x 10⁻²

= 1.2 N / C

4 0
3 years ago
Read 2 more answers
Change in velocity from 2 to -3
Alecsey [184]

Velocity units =m/s

Acceleration is the rate of change of velocity

a =timechange in velocity

Therefore SI units of acceleration is ms−1/s=s2m

5 0
3 years ago
A block of mass
Gennadij [26K]

(a) The work done by the applied force is 26.65 J.

(b) The work done by the normal force exerted by the table is 0.

(c) The work done by the force of gravity is 0.

(d) The work done by the net force on the block is 26.65 J.

<h3>Work done by the applied force</h3>

W = Fdcosθ

W = 14 x 2.1 x cos25

W = 26.65 J

<h3>Work done by the normal force</h3>

W = Fₙd

W = mg cosθ x d

W = (2.5 x 9.8) x cos(90) x 2.1

W = 0 J

<h3>Work done force of gravity</h3>

The work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.

<h3> Work done by the net force on the block</h3>

∑W = 0 + 26.65 J = 26.65 J

Thus, the work done by the applied force is 26.65 J.

The work done by the normal force exerted by the table is 0.

The work done by the force of gravity is 0.

The work done by the net force on the block is 26.65 J.

Learn more about work done here: brainly.com/question/8119756

#SPJ1

6 0
2 years ago
Which of these galaxies would you most likely find at the center of a large cluster of galaxies?
Paul [167]

Answer:

a large elliptical galaxy

Explanation:

4 0
2 years ago
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