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xeze [42]
3 years ago
6

Write the quadratic equation in standard form: -2x-12=-x^2

Mathematics
1 answer:
Soloha48 [4]3 years ago
3 0

Answer:

¯\_(ツ)_/¯

explainations completely right

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Find tan0, cos0, and csc0, where 0 is the angle shown in the figure. Give exact values, not decimal approximations. BRANLIEST!!​
Setler [38]

Answer:

see explanation

Step-by-step explanation:

We require to find the third side of the triangle.

Using Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x represent the third side, then

x² + 15² = 17², that is

x² + 225 = 289 ( subtract 225 from both sides )

x² = 64 ( take the square root of both sides )

x = \sqrt{64} = 8

Thus

tanΘ = \frac{opposite}{adjacent} = \frac{15}{8}

cosΘ = \frac{adjacent}{hypotenuse} = \frac{8}{17}

sinΘ = \frac{opposite}{hypotenuse} = \frac{15}{17}

cscΘ = \frac{1}{sin0} = \frac{1}{\frac{15}{17} } = \frac{17}{15}

7 0
3 years ago
Using the digits 1-7 to create a 7 digit number that can be rounded to 6,300,000
otez555 [7]
6,317,927 can be a 7 digit number that rounds to 6,300,000.

Hope this helps.
5 0
3 years ago
ZB = round your answer to the nearest hundredth PLEASE HELP
amm1812

Answer:

Boy a dont no but good luck

Step-by-step explanation:

i am not smart but sonthing like 67

5 0
3 years ago
2-(y + 2) = 3y<br> Solve for y
alexgriva [62]

Answer:

y=0

Step-by-step explanation:

Reorder the terms:

2 + -1(2 + y) = 3y

2 + (2 * -1 + y * -1) = 3y

2 + (-2 + -1y) = 3y

Combine like terms: 2 + -2 = 0

0 + -1y = 3y

-1y = 3y

Solving

-1y = 3y

Add '-3y' to each side of the equation.

-1y + -3y = 3y + -3y

Combine like terms: -1y + -3y = -4y

-4y = 3y + -3y

Combine like terms: 3y + -3y = 0

-4y = 0

Divide each side by '-4'.

y = 0

hope this helps

3 0
3 years ago
An ant is on top of a tree 23 meters tall,directly above her home, which is .3 meters below the ground
ollegr [7]

Answer:

so shes 26 meters above her home? i dont know what your asking tbh

Step-by-step explanation:

6 0
3 years ago
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