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3 years ago

12

PLEASE HELP ASAP!!! I WILL MARK YOU BRAINLIEST! What is P( 2 and B)?

1 answer:

8_murik_8 [283]3 years ago

7 0

Answer:

Step-by-step explanation:

Because there are 8 numbers and 6 letters.

P(2andB)=(1/8)(1/6)=1/48

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A pentigonal prism is cut by a plane perpendicular to the base. What is the shape of the cross section that is formed ?

Sholpan [36]

Answer:

In a right pentagonal prism, the bases are pentagons and the lateral faces are rectangles. If we take a cross-section perpendicular to the base, this same cross-section will be parallel to the lateral faces. This means it will be the same shape as the lateral faces, which is a rectangle.

Step-by-step explanation:

5 0

3 years ago

A rectangle has perimeter 20 m . Express the area of the rectangle as a function of the length of ones its side.

kondor19780726 [428]

Answer:

A = 10W - W²

Step-by-step explanation:

Perimeter of a rectangle = 2(L+W)

Area of a rectangle =LW

L is the length

W is the width

Given

Perimeter = 20m

20 = 2 (L+W)

10 = L+W

L = 10 - W ....2

Substitute equation 2 into the formula for calculating the area

Recall that A = LW

A = (10-W)W

A = 10W - W²

Hence the area of the rectangle as a function of the length of ones its side is expressed as A = 10W - W²

6 0

3 years ago

A rhombus has a side length equal to one of the diagonals. The other diagonal is 4cm longer. Find the area of the rhombus.

klasskru [66]

Answer:

The area of the rhombus is 25.83 cm².

Step-by-step explanation:

The area of a rhombus is given by:

$A = \frac{d_{1} \times d_{2}}{2}$

Where:

d₁: is one diagonal

d₂: is the other diagonal = d₁ + 4 cm

We know that one side length of the rhombus is equal to d₁. We can imagine a right triangle inside the rhombus, with the following dimensions:

h: hypotenuse of the right triangle

a: one side of the right triangle

b: is the other side of the right triangle

From the above we know that:

h = d₁

$a = \frac{d_{2}}{2} = \frac{d_{1} + 4}{2}$

$b = \frac{d_{1}}{2}$

We can find d₁ with Pitagoras:

$h^{2} = a^{2} + b^{2}$

$d_{1}^{2} = (\frac{d_{1} + 4}{2})^{2} + (\frac{d_{1}}{2})^{2}$

$d_{1}^{2} = \frac{1}{4}(d_{1}^{2} + 8d_{1} + 16 + d_{1}^{2})$

By solving the above quadratic equation for d₁ and taking the positive solution we have:

$d_{1} = 5.46 cm$

So, d₂ is:

$d_{2} = d_{1} + 4 = 5.46 cm + 4 cm = 9.46 cm$

Now, we can find the area:

$A = \frac{d_{1} \times d_{2}}{2} = \frac{5.46 cm \times 9.46 cm}{2} = 25.83 cm^{2}$

Therefore, the area of the rhombus is 25.83 cm².

I hope it helps you!

3 0

3 years ago

(8×1) + (5×1/100) + (9×1/1000)

Ghella [55]

Your answer is 8 + 5/100 + 9/1000 but in simplest form it would be 22/1100

4 0

3 years ago

Read 2 more answers

The scale of the map is missing.the actual distance from liberty to west quall is 72 miles,and it is 7 inches on the map.

storchak [24]

Scale = 72/7 = 10 2/7 miles per inch

(7-4) x 10 2/7 = 30.857142....miles from west quall

4 0

3 years ago

Read 2 more answers