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amid [387]
3 years ago
13

What is the value of f(-3) if f(x)=5(2-x)

Mathematics
2 answers:
Ahat [919]3 years ago
8 0

Answer:

The answer is 25.

Step-by-step explanation:

What you have to do here is just replace "x" in the equation with -3. In other words, you plug in -3 to f(x).

f(-3) = 5(2 - - 3).

To negatives makes a positive.

f(-3) = 5(2 + 3).

f(-3) = 5(5).

5 times 5 is 25.

f(-3) = 25.

So your answer is 25.

NISA [10]3 years ago
7 0

Answer:

the value of f(-3) is 25

Step-by-step explanation:  f(-3)                     f(x)=5(2-x)

If x=-3 and you subtract negative 3 from 2 you get a positive 5 and when you multiply across the parenthesies you get 25 so f(-3)=25

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a strip of paper is 9/10 of an inch long. you need to cut the paper into 3/12 inch pieces. how many pieces will you be able to c
e-lub [12.9K]
We have to divide 9/10 by 3/12.

if we divide by a fraction, we can instead multiply by it's inverse:

\frac{9}{12}/ \frac{3}{12}  = \frac{9}{12} * \frac{12}{3}

so now we count:

\frac{9}{12} * \frac{12}{3} =\frac{9}{1} * \frac{1}{3}=3

so we can cut exactly 3 pieces!



5 0
3 years ago
Use elimination to solve 3x-2y=24 x+2y=48
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Answer:

X= 18; Y=15

Step-by-step explanation:

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5 0
3 years ago
Jermaine has just painted a large mural. It is 8 1/2 feet wide. The wall he wants to place it on is 11 3/4 feet wide. About how
PolarNik [594]
First turn 1/2 to 2/4 so you have a common denominator.
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6 0
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Which graph represents the solution of the system?<br>x² + y² = 4 <br>x-y=1<br>​
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Answer:

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Step-by-step explanation:

5 0
3 years ago
For the system of equations that follows, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in
Rainbow [258]

Answer:

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Step-by-step explanation:

From the question we are told that

System of equations given as

x₁ + 3x₂ + x₃ + x₄ = 3;

2x₁ - 2x₂ + x₃ + 2x₄ = 8;

x₁ - 5x₂ + x₄ = 5

Matrix form

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}  \begin{Vmatrix}x_1\\x_2\\x_3\\x_4\end{Vmatrix}

Generally the echelon reduction is mathematically applied as

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -2 times the 1st row to the 2nd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & -8 & -1&0&2\\0&1 & -5 & 1& 5\end{Vmatrix}

Multiply the 2nd row by -1/8  

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -1 times the 2nd row to the 3rd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & -41/8 & 1& 21/4\end{Vmatrix}

Multiply the 3rd row by -8/41

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -1/8 times the 3rd row to the 2nd row

Add -1 times the 3rd row to the 1st row

\begin{Vmatrix}1 & 3 & 0&49/41&165/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -3 times the 2nd row to the 1st row

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

3 0
3 years ago
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