Question

Hich is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)? y squared over 40 minus x squared over 10 equals 1
y squared over 10 minus x squared over 15 equals 1
x squared over 10 minus y squared over 40 equals 1
x squared over 10 minus y squared over 15 equals 1

Answer 1

Answer:

Step-by-step explanation:

The foci are horizontally aligned, so the hyperbola is horizontal. The center is midway between foci, at (0,0).

y²/a² - x²/b² = 1

a² + b² = 5²

Directrices: x=± a²/5 = ±2

a=√10

b = √15

y²/10 - x²/15 = 1