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Anika [276]
3 years ago
7

Need help please ???????

Mathematics
1 answer:
abruzzese [7]3 years ago
4 0

Answer:

5pm

Step-by-step explanation:

5 x 4= 20 miles

4 x 5= 20 miles

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Let x1 = 12, y1 = 15, and y2 = 3. Let y vary inversely with x. Find x2.
vladimir1956 [14]

Answer:

x2 = 60

Step-by-step explanation:

If the variables x and y are inversely proportional, the product x * y is a constant.

So using x1 and y1 we can find the value of this constant:

x1 * y1 = k

12 * 15 = k

k = 180

Now, we can use the same constant to find x2:

x2 * y2 = k

x2 * 3 = 180

x2 = 180 / 3 = 60

So the value of x2 is 60.

3 0
3 years ago
Can anybody solve these two questions? Whoever gets it right gets brianleist.
qaws [65]

Answer:

7= 1

8= decimal : 0.00390625

try using symbolab.com

5 0
3 years ago
Read 2 more answers
Need help with linear approximation
Dmitrij [34]
Consider a function f(x), the linear approximation L(x) of f(x) is given by

L(x)=f(a)+(x-a)f'(a)

Given the quantity: \frac{1}{203}

We approximate the quantity using the function f(x)= \frac{1}{x}, where x = 203.

We choose a = 200, thus the linear approximation is given as follows:

L(203)=f(200)+(203-200)f'(200) \\  \\ = \frac{1}{200} - \frac{3}{200^2} = \frac{200-3}{200^2} = \frac{197}{40,000} =0.004925
5 0
3 years ago
Can I get some help? Thanks!
vivado [14]

Answer:

C: y=11x

Step-by-step explanation:

11x2=22

11x3=33

11x4=44

So on and so forth.

4 0
3 years ago
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2x^2y^3z^2 · 4xy^4x^2<br><br> Multiply and simplify
Advocard [28]

Take out the constants

(2 × 4)x^2xx^2y^3y^4z^2

Simplify 2 × 4 to 8

8x^2xx^2y^3y^4z^2

Use the Product Rule: x^ax^b = x^a + b

8x^2 + 1 + 2y^3 + 4z^2

Simplify 2 + 1 + 2 to 5

8x^5y^3 + 4z^2

Simplify 3 + 4 to 7

<u>8x^5y^7z^2</u>

6 0
3 years ago
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