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3 years ago

Equation A: y = x + 1

Mathematics

1 answer:

ratelena [41]3 years ago

5 0

The first step can be used to find the solutiuon to the set of equations what is

x+1 = 4x +5

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What is the probability of rolling a dice 3 times in a row and all 3 rolls landing on a number greater than 1.

inessss [21]

Answer:

0.58

Step-by-step explanation:

P1 > 1 = 5/6

P2 > 1 = 5/6

P3 > 1 = 5/6

P1*P2*P3 = 5/6*5/6*5/6

P = 0.58

8 0

3 years ago

Find the slope of the line containing the points (1, 4) and (3, 7).

irina1246 [14]

Answer: 3/2

Step-by-step explanation:

the formula to find slope is:

m = rise/run = $\frac{y2-y1}{x2-x1}$

In this case:

m = 3/2 = $\frac{7-4}{3-1}$

6 0

3 years ago

Help on this question please. What is the perimeter of ABC?

mestny [16]

Answer:

Step-by-step explanation

5x2=10

3x2=6

2x2=4

the answer would be 20

8 0

3 years ago

Read 2 more answers

How to differentiate ?

Bas_tet [7]

Use the power, product, and chain rules:

$y = x^2 (3x-1)^3$

• product rule

$\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2)}{\mathrm dx}\times(3x-1)^3 + x^2\times\dfrac{\mathrm d(3x-1)^3}{\mathrm dx}$

• power rule for the first term, and power/chain rules for the second term:

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(x-1)^2\times\dfrac{\mathrm d(3x-1)}{\mathrm dx}$

• power rule

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(3x-1)^2\times3$

Now simplify.

$\dfrac{\mathrm dy}{\mathrm dx} = 2x(3x-1)^3 + 9x^2(3x-1)^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2 \times (2(3x-1) + 9x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2(15x-2)}$

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.

On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

$\ln(y) = \ln\left(x^2(3x-1)^3\right) \\\\ \ln(y) = \ln\left(x^2\right) + \ln\left((3x-1)^3\right) \\\\ \ln(y) = 2\ln(x) + 3\ln(3x-1)$

Differentiate both sides and you end up with the same derivative:

$\dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac2x + \dfrac9{3x-1} \\\\ \dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \times x^2(3x-1)^3 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(15x-2)(3x-1)^2$

7 0

3 years ago

PLS HELP ILL GIVE BRAINLIEST.

liberstina [14]

Answer:

Step-by-step explanation:

I think it increased by 20% I think or it’s 25% think

3 0

3 years ago