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elena-s [515]
3 years ago
7

PLZ HELP! IM GIVING EXTRA POINTS!

Mathematics
2 answers:
horsena [70]3 years ago
8 0
3  (4r+y) if it dont help let me know
zhenek [66]3 years ago
7 0
I hope this helps you




3 and (4r+y)
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Kami is cooking dinner for a family reunion that 21 people are attending.
Ksivusya [100]
The answer it 33.6 oz (D)
5 0
2 years ago
3 times what gives me a sum of 24? im trying to finish my homework so please help.
Leno4ka [110]
It is not a sum, it is a product.

3 times x = 24   (write equation)
           3x = 24  (isolate x by dividing the coefficient, 3, on both sides)
           /3     /3
             x = 8    (this i your answer)

Therefore 3 times 8 gives you 24.
4 0
2 years ago
Read 2 more answers
A computer software retailer used a mark up of 150%. Find the cost of the computer
cluponka [151]

The selling price of the computer is $35.

4 0
2 years ago
Using one complete sentence give a mathmatical definition of zero
just olya [345]

Answer:

Zero is an integer which is indicated by the symbol 0 in numbers and it is used to indicate that the count of an item when there are non of the item present which is one of the reasons zero along with the fact that it is the number between positive and negative numbers, why it is not associated with a positive or negative sign.

Step-by-step explanation:

A number which is not zero is said to be a non-zero number and the roots of a function is known as the zeros of the function.

5 0
2 years ago
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
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