Answer:
The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.
Step-by-step explanation:
i think this would help
Its C or the 3rd option
(9x+2)
You have to inverse the equation meaning do everything the opposite so for example, add the 2 to the other side of the equation
4.4
4 5/13 = 4 + 5/13 = 4 + 0.384615... = 4.384615...
Answer: 4.4
Answer: C. “BEC”
