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devlian [24]
3 years ago
14

URGENT! A ball gets hit upwards from a height of 5ft and an initial velocity of 200f/s. When does the ball hit the ground to the

nearest tenth of a section?
Mathematics
1 answer:
Vinil7 [7]3 years ago
5 0

Answer:

The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.

Step-by-step explanation:

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The work of a student to solve the equation 3(2x – 4) = 8 + 2x + 6 is shown below:
Blababa [14]
If you would like to know in which step did the student first make an error and what is the correct step, you can calculate this using the following steps:

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6 0
3 years ago
Need some help with the answer to the question
kicyunya [14]

Answer:

(- 4, 27 )

Step-by-step explanation:

Equate the right sides of both equations, that is

x² - 2x + 3 = - 2x + 19 ← subtract - 2x + 19 from both sides

x² - 16 = 0 ← in standard form

(x - 4)(x + 4) = 0 ← in factored form

Equate each factor to zero and solve for x

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2 years ago
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