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devlian [24]
4 years ago
14

URGENT! A ball gets hit upwards from a height of 5ft and an initial velocity of 200f/s. When does the ball hit the ground to the

nearest tenth of a section?
Mathematics
1 answer:
Vinil7 [7]4 years ago
5 0

Answer:

The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.

Step-by-step explanation:

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OverLord2011 [107]

Answer:

dx/dt = 5√5/2

Step-by-step explanation:

Given:

dx/dt = 25 feet per second

According to Pythagoras theorem:

x² + 90² = y²

We know that x = 30 ft

So,

x² + 90² = y²

30² + 90² = y²

y = 30√10

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x² + 90² = y²

By taking differentiate:

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[x/y][dx/dt] = dy/dt

dx/dt = 5√5/2

4 0
3 years ago
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ki77a [65]

Answer:

-78/30 or -2 3/5

Step-by-step explanation:

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8 0
3 years ago
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Which quadratic function is represented by the table ???
Ulleksa [173]

Answer:

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Step-by-step explanation:

To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.

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A.   3(-2)² + 2(-2) - 5 =

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= 21

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8 0
3 years ago
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mestny [16]

Answer:

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Step-by-step explanation:

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Naily [24]

Answer:

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Step-by-step explanation:

because if you do all the work it's just a waste of time when you could get the same answer by just adding a zero.

4 0
3 years ago
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