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2 years ago

ILL BRAINLIEST YOU HELP ME PLEASE

Mathematics

1 answer:

raketka [301]2 years ago

8 0

Answer:

A = (0, -3)

B = (0, 0)

C = (-2, 0)

D = (-2, -3)

Step-by-step explanation:

The figure is being rotated 90° counterclockwise that's why it's now located in Q III. B remains the same since it's our turning point. Correct me if I'm wrong. I hope it helps.

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What is the domain function on the graph

sattari [20]

ANSWER

All real numbers greater or equal to -3.

EXPLANATION

The domain of the given function are values of x that make the function defined.

We can see from the graph that, the domain are x-values greater than or equal to -3.

In other words, we can find a corresponding y-value for all x-values greater than or equal to -3.

The correct answer is option D.

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Fynjy0 [20]

Answer:

32.1

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2 years ago

If you needed to triple a recipe, would the ratio change? Explain.

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2 years ago

(look at the images) can i get help on these?

Svetlanka [38]

Answer:

see explanation

Step-by-step explanation:

JK + KL = JL , substitute values

2x + 1 + 6x = 81, that is

8x + 1 = 81 ( subtract 1 from both sides )

8x = 80 ( divide both sides by 8 )

x = 10

Thus JK = 2x + 2 = 2(10) + 1 = 20 + 1 = 21

KL = 6x = 6 × 10 = 60

--------------------------------------------------------------

JK + KL = JL , substitute values

2x + x + 2 = 5x - 10 , that is

3x + 2 = 5x - 10 ( subtract 3x from both sides )

2 = 2x - 10 ( add 10 to both sides )

12 = 2x ( divide both sides by 2 )

6 = x

Thus

JK = 2X = 2 × 6 = 12

KL = x + 2 = 6 + 2 = 8

JL = 5x - 10 = 5(6) - 10 = 30 - 10 = 20

------------------------------------------------------------

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = S(7, 3) and (x₂, y₂ ) = T(1, - 5)

d = $\sqrt{(1-7)^2+(-5-3)^2}$

= $\sqrt{(-6)^2+(-8)^2}$

= $\sqrt{36+64}$

= $\sqrt{100}$ = 10

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2 years ago