Answer:
31.3%
Step-by-step explanation:
Start by doing the binomial expansion of (x+y)^6 where x represents success. This is
(x^6y^0) + 6(x^5y^1) +15(x^4y^2) +20(x^3y^3) +15(x^2y^4) +6(x^1y^5) +(x^0y^6)
We are interested in the x^3y^3 term which represents exactly 3 successes. Since the probability of success and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is
20/64 = .3125 which is 31.25% Rounding yo the nearest tenth gives us
nuuuu the picture is blocked im on my school computer sorry :(
Answer:
Try solving 6(n-5)-2.
Step-by-step explanation:
I believe this can be set up as 6(n-5)-2. The difference of a number and five can be represented by n-5. If this needs to be multiplied by 6 (hence 6 times), it would become 6(n-5). Two less than that is represented by -2. Thus, two less than six times the difference of a number and five is 6(n-5) -2, which, when n=9 is plugged in, looks like 6(9-5) -2. Follow PEMDAS from there.
1 nickel = 5 cents
1 dime = 10 cents
13 nickels = 13 *5 = 65 cents
6 dimes = 6*10 = 60 cents.
Total = 65 + 60 = 125 cents.
= 125 cents or $1.25
N and d are both numbers of thousands of dollars.
Thus, if n = 1, that means $1000.
Here n = d + 0.4.
Note that in C, n+0.04=n is completely wrong.
Similarly, in D, d = 0.04 = n is completely wrong.
The "combined profit amount" for Nov. and Dec. is n + d = 3.15.
Only A matches this info. Your answer is A.
