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gavmur [86]
3 years ago
14

Need help plz

Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

Answer:

Z

y

x

Step-by-step explanation:

zy

xz

xy

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chad buys peanut in 2-pound bags.He repackages them into bags that hold 5/6 pound of peanuts.How many 2-pound bags of peanuts sh
Nataliya [291]
First, let's find out how many 5/6 pound bags he can fill with on 2 pound bag.

2 divided by 5/6
2 x 6/5
2.4

He can fill 2.4 bags with one 2 bag.
Now we just need to multiply 2.4 by a number that will make it a whole number. You can use the guess and check method starting with 2 to figure your answer out, but 2.4 x 5 = 12 which is a whole number.

This means that Chad needs to buy 5 of the 2 pound bags to fill 12 of the 5/6 pound bags, and he will not have peanuts leftover

6 0
4 years ago
Use the identity (x+y)(x2−xy+y2)=x3+y3 to find the sum of two numbers if the product of the numbers is 10, the sum of the square
professor190 [17]

Answer:

The sum of two numbers is 7.

Step-by-step explanation:

Given : the product of the numbers is 10, the sum of the squares of the numbers is 29, and the sum of the cubes of the numbers is 133.

Using identity (x+y)(x^2-xy+y^2)=x^3+y^3 and given details, we have to find the sum of two numbers.

Since, given that the product of the numbers is 10 that is xy=10

Also, given the sum of the squares of the numbers is 29 that is x^2+y^2=29

and the sum of the cubes of the numbers is 133 that is x^3+y^3=133

Using, the given identity (x+y)(x^2-xy+y^2)=x^3+y^3,

Substitute, the given values, we have,

(x+y)(29-10)=133

Simplify , we get,

(x+y)(19)=133

Divide both side by 19, we have,

(x+y)=7

Thus, the sum of two numbers is 7.

7 0
4 years ago
Read 2 more answers
Mrs Rodriguez will make name tags for each of the 45 choir members and 30 orchestra members the materials for each name tag cost
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45 x 0.44 = ?
30 x 0.44 = ?

Then add the two answers together.
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Since there are 6 possibilities, the probability of rolling either an X or V is:

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Solve for x and graph the solution on the number line below.
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