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3 years ago

‘write an equation of the line that passes through each pair of points’ (1,2) and (4,8)

Mathematics

1 answer:

Levart [38]3 years ago

8 0

Hi there!

Step-by-step explanation:

$Slope=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}$

$\frac{8-2}{4-1}=\frac{6}{3}=2$

So therefore, the slope is 2.

Final answer is 2.

*The answer must have a positive sign.*

I hope this helps you!

Have a nice day! :)

-Charlie

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6 1/2 divided by 3/4 pls someone help ASAP

e-lub [12.9K]

Answer:

Its basically asking 6.50 / .75 which is 8.6 or you can round it to 8.7

Step-by-step explanation:

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2 years ago

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Number 2 and please provide a step by step explanation!!!!

Alekssandra [29.7K]

The number of students in 5th grade is 60, since 24% of 250 is 60.

Since 90 is 38% if 250, 38 is going to be the percent of all students in sixth grade.

20% of 250 is 50, so the percent of all students in seventh grade is 50.

Finally, 45 is 18% of 250, so 18 percent of all students are in eight grade.

Hope this helped :)

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2 years ago

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3x−8≤23 OR −4x+26≥6 solve for x

Mama L [17]

Answer:

x ≤ 31/3

Step-by-step explanation:

5 0

3 years ago

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hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago

Solve for x, -3x = -15

Goshia [24]

Answer:

x=5

Step-by-step explanation:

so to isolate the x you dived the -3 to both sides

so it will now be

x=5 because a negative times or divided by a negative equals a positive so to prove that x=5

-3(5)=-15

which is true

5 0

3 years ago

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