Brady studied for 4.5 hours that week
How we determine the total study hours?
The total study hours for Brady is the sum of the hours used in studying on Monday, Tuesday, Wednesday and Thursday.
He studied for 1.5 hours on Monday
He studied for 0.75 hours on Tuesday
He studied again for 1.25 hours on Wednesday
Lastly, he studied for 1 hour on Thursday, the last day
Total number of study hours=1.5+0.75+1.25+1
Total number of study hours=4.50
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Answer: yes
Step-by-step explanation:
4 4/16 + 3 3/8=4 2/8 + 3 3/8=7 5/8
56/74 = 28/37
y^-2
s^2
3a/4a
7g/12g
0.5p^-1
2/7k^3
2b/3d
An equal mass of silver will displace a different volume of fluid than that displaced by gold.
<h2>Archimedes principle</h2>
According to the Archimedes principle, when an object is partially or completely immersed in water, the object will experience a force that displaces its own weight of fluid.
Therefore, when the jeweler deceptively replaced “an equal weight” (or equal mass) of gold with silver, we can know that by observing the volume of water displaced in each case. An equal mass of silver will displace a different volume of fluid than that displaced by gold.
Learn more about Archimedes principle: brainly.com/question/13106989
Answer:
y_c = 2 + 10*x
Step-by-step explanation:
Given:
y'' = 0
Find:
- The solution to ODE such that y(0) = 2, y'(0) = 10
Solution:
- Assuming a solution y = Ce^(mt)
So, y' = C*me^(mt)
y'' = C*m^2e^(mt)
- Back substitute into given ODE, we get:
y'' = C*m^2e^(mt) = 0
e^(mt) can not be equal to zero
- Hence, m^2 = 0
m = 0 , 0 - (repeated roots)
- The complimentary function for repeated roots is:
y_c = (C1 + C2*x)*e^(m*t)
y_c = C1 + C2*x
- Evaluate @ y(0) = 2
2 = C1 + C2*0
C1 = 2
-Evaluate @ y'(0) = 10
y'(t) = C2 = 10
Hence, y_c = 2 + 10*x