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iVinArrow [24]
3 years ago
9

What is the GCF of 45,85and90

Mathematics
1 answer:
labwork [276]3 years ago
4 0
45 = 1, 3, 5, 9, 15, 45
85 = 1, 5, 17, 85
90 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

So, greatest common factor is 5
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Brady studied 1.5 hours on Monday, 0.75 hours on Tuesday, 1.25 hours on Wednesday, and 1 hour on Thursday. How
Advocard [28]

Brady studied for 4.5 hours that week

How we determine the total study hours?

The total study hours for Brady is the sum of the hours used in studying on Monday, Tuesday, Wednesday and Thursday.

He studied for 1.5 hours on Monday

He studied for 0.75 hours on Tuesday

He studied again for 1.25 hours on Wednesday

Lastly, he studied for 1 hour on Thursday, the last day

Total number of study hours=1.5+0.75+1.25+1

Total number of study hours=4.50

Find out more about study hour on: brainly.com/question/876733

#SPJ1

8 0
2 years ago
kirby wants to run a total of 7 5/8 miles every tuesday and thursday. if he runs 4 4/16 miles on tuesday and 3 3/8 miles every t
mylen [45]

Answer: yes


Step-by-step explanation:

4 4/16 + 3 3/8=4 2/8 + 3 3/8=7 5/8

8 0
3 years ago
What is 81/90 in simplest form?
Brums [2.3K]
56/74 = 28/37
y^-2
s^2
3a/4a
7g/12g
0.5p^-1
2/7k^3
2b/3d

7 0
3 years ago
Please help ASAP! Willing to give brainliest if correct!
Vsevolod [243]

An equal mass of silver will displace a different volume of fluid than that displaced by gold.

<h2>Archimedes principle</h2>

According to the Archimedes principle, when an object is partially or completely immersed in water, the object will experience a force that displaces its own weight of fluid.

Therefore, when the jeweler deceptively replaced “an equal weight” (or equal mass) of gold with silver, we can know that by observing the volume of water displaced in each case. An equal mass of silver will displace a different volume of fluid than that displaced by gold.

Learn more about Archimedes principle: brainly.com/question/13106989

6 0
3 years ago
The differential equation y′′=0 has one of the following two parameter families as its general solution: yyyy=C1ex+C2e−x=C1cos(x
svet-max [94.6K]

Answer:

y_c = 2 + 10*x

Step-by-step explanation:

Given:

                                                y'' = 0

Find:

- The solution to ODE such that y(0) = 2, y'(0) = 10

Solution:

- Assuming a solution y = Ce^(mt)

So,                                y' = C*me^(mt)

                                    y'' = C*m^2e^(mt)

- Back substitute into given ODE, we get:

                                    y'' = C*m^2e^(mt) = 0

                                    e^(mt) can not be equal to zero

- Hence,                       m^2 = 0

                                     m = 0 , 0 - (repeated roots)

- The complimentary function for repeated roots is:

                                    y_c = (C1 + C2*x)*e^(m*t)

                                    y_c = C1 + C2*x  

- Evaluate @ y(0) = 2

                                    2 = C1 + C2*0

                                    C1 = 2

-Evaluate @ y'(0) = 10

                                    y'(t) = C2 = 10

Hence,                         y_c = 2 + 10*x

5 0
3 years ago
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