What is the value of f(1) when f(x)=3x^3-2x^2-3x+18

1 answer:

4 0

Answer:

f(1) = 16

Step-by-step explanation:

f(1) = $3(1)^{2} -2(1)^{2} -3(1)+18$

f(1) = $3-2-3+18$

f(1) = 16

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