Question

What is the twelfth term in the sequence 13, 26, 39, …?

Answer 1

Answer:

the answer is 156

Step-by-step explanation:

for my own method

13 is the sequence

so 13×12=156

or

13+13=26+13=39+13=52+13=65+13=78+13=91+13=104+13=117+13=130+13=143+13=156.

so that is the final answer

Answer 2

Answer:

• 156

Step-by-step explanation:

Given the sequence

• 13, 26, 39, …

We see it is an AP with

• The first term a = 13
• Common difference d = 13 ( as 26 - 13 = 39 - 26 = 13)

The 12th term is:

• a₁₂ = a + 11d = 13 + 11*13 = 156