What is the twelfth term in the sequence 13, 26, 39, …?
2 answers:
Answer:
the answer is 156
Step-by-step explanation:
for my own method
13 is the sequence
so 13×12=156
<h3> or</h3>
13+13=26+13=39+13=52+13=65+13=78+13=91+13=104+13=117+13=130+13=143+13=156.
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Answer:
Step-by-step explanation:
<u>Given the sequence </u>
<u>We see it is an AP with</u>
- The first term a = 13
- Common difference d = 13 ( as 26 - 13 = 39 - 26 = 13)
<u>The 12th term is:</u>
- a₁₂ = a + 11d = 13 + 11*13 = 156
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