A ball is dropped from a height of 8 feet. If every time it bounces, it bounces 60% of its previous height, what is the total di
1 answer:
Answer:
<h3>20feet</h3>Step-by-step explanation:
Initial height of the ball = 8feet
If it bounces 60% of its previous height, its new height will be;
60% of 8
= 60/100 * 8
= 480/100
= 4.8 ft
If it bounces 60% of its current distance, new height will be expressed as;
60% of 4.8
= 0.6 * 4.8
= 2.88
The height of the ball will keep reducing and form a geometric progression of the form 8, 4.8, 2.88...
In order to get the total distance traveled by the ball, we need to calculate the sum to infinity of the sequence;
S∞ = a/1-r where;
a is the first term = 8
r is the common ratio
Substitute into the formula;
S∞ = a/1-r
S∞ = 8/1-0.6
S∞ = 8/0.4
S∞ = 20feet
Hence the total distance traveled by the ball is 20feet
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A. .1070
Step-by-step explanation:
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A. .1070