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3 years ago

a triangular land having area 36m²and perimeter 84 m has length of the edge 26m. Calculate the measure of remaining two sides

Mathematics

1 answer:

faust18 [17]3 years ago

3 0

Complete question :

a triangular land having area 36m²and perimeter 84 m has length of the edge 26m. Calculate the measure of remaining two sides

Answer:

28cm, 30 cm

Step-by-step explanation:

Area = 336 m³ ; lebgth of edge = 26

Perineter, p = 84

Perimeter of triangle :

a + b + c

Length of other two sides = 84 - 26 = 58

If length of one of the sides = x

Lenvyb if the other = 58 - x

From Hero's formular :

Sqrt(s(s-a)(s-b)(s-c).

s = perimeter /2 = 84/2 = 42

Sqrt(42(42 - 26)(42 - x)(42 - (58-x))

sqrt(42(16)(42-x)(42-58+x) = 336

sqrt(42(16)(42-x)(-16+x) = 336

672(42-x)(x - 16) = 112896

(42 - x)(x - 16) = 168

42x - 672 - x² + 16x = 168

-x² + 58x - 840 = 0

Using the quadratic equation solver, the roots are :

28, 30

Hence.the other tow sides are 28 cm and 30 cm

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Complete question :

The average amount that a college student spends on a textbook is $205 with a

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Answer:

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Step-by-step explanation:

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3 years ago

Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and the sample size.

pentagon [3]

Answer:

$\bar X= \mu = 25$

$\sigma_{\bar X}= \frac{7}{\sqrt{15}}= 1.807$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the following conditions

Where $\mu=25$ and $\sigma=7$

And for this case we select a sample size of n= 15. and we want to know the distribution for the sample mean $\bar X$ . We can assume that the distribution for $\bar X$ is approximately normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Asuming that the distribution for X is also approximately normal. So then the parameters are:

$\bar X= \mu = 25$

$\sigma_{\bar X}= \frac{7}{\sqrt{15}}= 1.807$

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3 years ago

a triangular land having area 36m²and perimeter 84 m has length of the edge 26m. Calculate the measure of remaining two sides​

a triangular land having area 36m²and perimeter 84 m has length of the edge 26m. Calculate the measure of remaining two sides