2 years ago

Given that sine of theta = 21/29, what is the value of cosine of theta, for 0° < theta < 90°?

Mathematics

1 answer:

fenix001 [56]2 years ago

7 0

If the value of θ is 46.4°. Then the value of the cosine of θ will be 20/29.

<h3>What is trigonometry?</h3>

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The value of sine of θ is 21/29.

Then the value of θ will be

sin θ = 21/29

θ = sin⁻¹(21 / 29)

θ = 46.4°

Then the value of the cosine of θ will be

cos θ = cos 46.4°

cos θ = 20/29

More about the trigonometry link is given below.

brainly.com/question/22698523

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