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kozerog [31]
3 years ago
11

Who knows how to solve the navier stokes equation

Mathematics
1 answer:
tankabanditka [31]3 years ago
3 0

Answer:

Nobody on this website XD



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Help plsssssssssssss
jonny [76]

Answer:

144

Step-by-step explanation:

72% of 200 is 144

Equation: 0.72*200 = 144

7 0
2 years ago
Read 2 more answers
Find the midpoint of the line segment joining the points (-2, -1) and (-8,12).
SCORPION-xisa [38]

x¹ = -2 x² = -8

y¹ = -1 y² = 12

Using midpoint formula,

M = ( x¹ + x²/2 ,y¹ + ý²/2)

or,M ={ -2+(-8)/2 , (-1) +12/2}

or, =( -10/2 , 11/2)

:M = ( -5 , 11/2)

6 0
2 years ago
PLEASE HELP ME! IT WOULD BE VERY MUCH APPRECIATED!
RideAnS [48]

Answer:

tooo dificult

Step-by-step explanation:

You know that I can't solve this right?

8 0
2 years ago
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5. One canned juice drink is 15% orange juice; another is 10% orange juice. How many liters of each should be mixed together in
hram777 [196]
X: liters of 15% orange juice
y: liters of 10% orange juice

x+y=5L

y=5L - x

x liters of 15% orange juice plus y liters of 10% orange juice makes 5 liters of 12% orange juice in equation form:

0.15x+0.10y = 0.12(5L)

0.15x+0.10(5L-x)=0.12(5L)

0.15x+0.5-0.10x=0.6

0.05x=0.1L

x=2L

so y = 3L

so you need 2 liters of 15% orange juice and 3 liters of 10% orange juice
4 0
3 years ago
A quality control inspector has drawn a sample of 19 light bulbs from a recent production lot. If the number of defective bulbs
Inessa05 [86]

Answer:

0.0016283

Step-by-step explanation:

Given that:

Proportion of defective bulbs, p = 30% = 0.3

Sample size, n = 19 bulbs

Probability that the lot will pass inspection :

P(none of the 19 is defective) Or P(only one of the 19 is defective)

P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19

0.7^19 = 0.0011398

P(only one of the 19 is defective) :

P(1 defective) * P(18 not defective )

(0.3) * (1 - 0.3)^18

0.3 * 0.7^18

0.3 * 0.001628413597910449 = 0.0004885

Hence,

P(none of the 19 is defective) + P(only one of the 19 is defective)

0.0011398 + 0.0004885) = 0.0016283

8 0
3 years ago
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