Answer:
1. The formula used to the find distance formula is: ![Distance\:Formula=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=Distance%5C%3AFormula%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
2. The distance between the points (-3,8) and (-4, -2) is 10.04
Step-by-step explanation:
1. Which of the following is the correct form of the distance formula?
The formula used to the find distance formula is: ![Distance\:Formula=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=Distance%5C%3AFormula%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
2. Use the distance formula to find the distance between the points (-3.8) and (-4. -?)
<em>Note: Since the y-term in (-4,-) is missing So, I am using -2 to solve the question and find distance. You can use the term given in question and replace it with -2 and use this solution as reference to solve and find the correct answer.</em>
We have points (-3,8) and (-4,-2)
Putting values in distance formula and finding result:
![Distance\:Formula=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=Distance%5C%3AFormula%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
We have x_1=-3, y_1=8, x_2=-4, y_2=-2
![Distance=\sqrt{(-2-(-3))^2+(-2-8)^2}\\Distance=\sqrt{(-2+3)^2+(-2-8)^2}\\Distance=\sqrt{(1)^2+(-10)^2}\\Distance=\sqrt{1+100}\\Distance=\sqrt{101}\\Distance=10.04](https://tex.z-dn.net/?f=Distance%3D%5Csqrt%7B%28-2-%28-3%29%29%5E2%2B%28-2-8%29%5E2%7D%5C%5CDistance%3D%5Csqrt%7B%28-2%2B3%29%5E2%2B%28-2-8%29%5E2%7D%5C%5CDistance%3D%5Csqrt%7B%281%29%5E2%2B%28-10%29%5E2%7D%5C%5CDistance%3D%5Csqrt%7B1%2B100%7D%5C%5CDistance%3D%5Csqrt%7B101%7D%5C%5CDistance%3D10.04)
So, the distance between the points (-3,8) and (-4, -2) is 10.04
The answer is C. you are usually only charged interest by your bank when you barrow more than your credit limit.
The answer for that is 7/100 but i think they are looking for 1/100
Answer:
<u>x</u><u> </u><u>is</u><u> </u><u>5</u>
Step-by-step explanation:
![\frac{4x - 5}{9x - 5} = \frac{3}{8} \\ \\ 8(4x - 5) = 3(9x - 5) \\ 32x - 40 = 27x - 15 \\ 5x = 25 \\ x = \frac{25}{5} \\ \\ x = 5](https://tex.z-dn.net/?f=%20%5Cfrac%7B4x%20-%205%7D%7B9x%20-%205%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B8%7D%20%20%5C%5C%20%20%5C%5C%208%284x%20-%205%29%20%3D%203%289x%20-%205%29%20%5C%5C%2032x%20-%2040%20%3D%2027x%20-%2015%20%5C%5C%205x%20%3D%2025%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B25%7D%7B5%7D%20%20%5C%5C%20%20%5C%5C%20x%20%3D%205)