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pav-90 [236]
3 years ago
6

Please help I’ll give brainliest

Mathematics
1 answer:
wolverine [178]3 years ago
5 0

Answer:

y=1/2×+4

Step-by-step explanation:

i think that the answer

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What are the solutions of the equation f(x) = g(x), given the following:
emmainna [20.7K]
F(x) = g(x) for x = 1 and x = 3.  Verify that for yourself.
7 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
I have 5 numbers in a data set that have:
CaHeK987 [17]

Answer:

2,2,3,4,5

Step-by-step explanation:

Just show how to get the mean, median, mode, and range to justify the answer

Also hey Brailen

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3 years ago
What is 12+[(14-6)/4]
saveliy_v [14]

Answer:

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Step-by-step explanation:

THE ANSWER TO THE PROBLEM IS 14

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This is a picture of a square pyramid and the net for the square pyramid. What is the surface area of the square pyramid? 108 ft
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The answer is 240ft^2. The area of the square base is 64 ft and the area of all four triangles is 176ft.
4 0
3 years ago
Read 2 more answers
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