F(x) = g(x) for x = 1 and x = 3. Verify that for yourself.
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
Answer:
2,2,3,4,5
Step-by-step explanation:
Just show how to get the mean, median, mode, and range to justify the answer
Also hey Brailen
Answer:
14
Step-by-step explanation:
THE ANSWER TO THE PROBLEM IS 14
The answer is 240ft^2. The area of the square base is 64 ft and the area of all four triangles is 176ft.