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2 years ago

If r(x) = 2x^2 – 5x + 1, find r(x + 2)

Mathematics

1 answer:

quester [9]2 years ago

3 0

Step-by-step explanation:

1 Expand by distributing terms.

rx+r×2

2 Regroup terms.

rx+2r

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Identify the type of data (qualitative/quantitative) and the level of measurement for the following variable. Explain your choic

AleksAgata [21]

Answer:

Option C. Quantitative, because numerical values, found by either measuring or counting, are used to describe the data.

Step-by-step explanation:

We are given the following in the question:

Variable: Final exam scores (from 0 to 100) for graduating high school seniors.

The following variable is a quantitative variable.

Quantitative variable:

Their values are expressed in numerical.
They are either measured or counted.
Descriptive terms are not used to describe them.
They can either be continuous or discrete.

Since final scores have numerical values and are counted, they are quantitative variables.

Option C. Quantitative, because numerical values, found by either measuring or counting, are used to describe the data.

Level of measurement:

A score of zero means no true existence for score. That is true zero exist.

Thus, it is ratio because difference between the values in data can be compared meaningful and they have a true zero.

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3 years ago

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Sergio [31]

Answer:

Step-by-step explanation:

A WOMEN WOULD OVER HER LIFE THE TFR SO IF YOU RELATE THAT TO GOATS THE MALE BRITISH AND THE FEMALE BIRTH WOULD BE DEFERRED SO THE PROBABILITY WOULD BE WORSE.

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2 years ago

What's the simplist way to simplify 13/78

Andrews [41]

13/78 simplified is 1/6

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3 years ago

Read 2 more answers

Use the sample information 11formula13.mml = 37, σ = 5, n = 15 to calculate the following confidence intervals for μ assuming th

bija089 [108]

Answer & Step-by-step explanation:

The confidence interval formula is:

I (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proposition of the distribution tails that are outside the confidence interval. In this case, 10% because 100-90%

σ= standard deviation. In this case 5

mean= 37

n= number of observations. In this case, 15

(a)

Z(alpha/2)= is the critical value of the standardized normal distribution. The critical valu for z(5%) is 1.645

Then, the confidence interval (90%):

I 90%(μ)= 37+- [1.645*(5/sqrt(15))]

I 90%(μ)= 37+- [2.1236]

I 90%(μ)= [37-2.1236;37+2.1236]

I 90%(μ)= [34.8764;39.1236]

(b)

Z(alpha/2)= Z(2.5%)= 1.96

Then, the confidence interval (90%):

I 95%(μ)= 37+- [1.96*(5/sqrt(15)) ]

I 95%(μ)= 37+- [2.5303]

I 95%(μ)= [37-2.5303;37+2.5303]

I 95%(μ)= [34.4697;39.5203]

(c)

Z(alpha/2)= Z(0.5%)= 2.5758

Then, the confidence interval (90%):

I 99%(μ)= 37+- [2.5758*(5/sqrt(15))

I 99%(μ)= 37+- [3.3253]

I 99%(μ)= [37-3.3253;37+3.3253]

I 99%(μ)= [33.6747;39.3253]

(d)

C. The interval gets wider as the confidence level increases.

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3 years ago

The 40th parallel of north latitude runs across the United States through Philadelphia, Indianapolis, and Denver. At this latitu

Ronch [10]

Answer:

793.25 mi/hr

Step-by-step explanation:

Given that:

The radius of the earth is = 3030 miles

The angular velocity = $\dfrac{\pi}{12} rads$

If a jet flies due west with the same angular velocity relative to the ground at the equinox;

We are to determine the How fast in miles per hour would the jet have to travel west at the 40th parallel for this to happen.

NOW;

Distance s is expressed by the relation

s = rθ

$s = 3030(\frac{\pi}{12} )$

s = 793.25

The speed which depicts how fast in miles per hour the jet would have traveled is :

$speed (v) = \frac{s}{t}$

$v = \frac{793.25}{1}$

v = 793.25 mi/hr

Hence, the jet would have traveled 793.25 mi/hr due west at the 40th parallel for this to happen.

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3 years ago