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2 years ago

Find the unit rate if, 350 miles needs 14 gallons of gas.

Mathematics

2 answers:

Mumz [18]2 years ago

7 0

Answer:

1 gallon = 25 miles

Step-by-step explanation:

350 mi 14 gallons =

350 = x Underline = fraction bar btw

14 1

use cross mulitplication

350 = 14x

25 = x

So one gallon goes 25 miles

Hope this helps!

Pls Remember to mark brainliest

expeople1 [14]2 years ago

5 0

Answer:

Step-by-step explanation:

Step 1: 350:14

Step 2: 175:7

Step 3: 7/7= 1

Step 4: 175/7=25

350:14=25:1

The car will run 25 miles for each gallon of gas

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Mr. Gutierrez had $100 to purchase candy for his students that completed their work. He

Sidana [21]

Answer:

$21.50

Step-by-step explanation:

Mr. Gutierrez had $100 to purchase candy for his students that completed their work.

He bought 8 bags of jolly ranchers

Each bag of jolly ranchers cost $3.25.

Hence, the cost of 8 bags of jolly ranchers = 8 × $3.25

= $26

He also bought 25 bags of assorted chocolate and each bag of assorted chocolate cost $2.10.

Hence, the cost of 25 bags of assorted chocolates = 25 × $2.10

= $52.5

Therefore, the amount of money Mr. Gutierrez has left over after these purchases is calculated as:

Total amount - Sum of ( Cost of 8 bags of jolly ranchers + 25 bags of assorted chocolates)

= $100 - ( $26 + $52.5)

= $100 - $78.50

= $21.50

7 0

3 years ago

PLEASE SHOW FULL SOLUTIONS !!!!! WILL MARK BRAINLIEST FOR THE BEST ANSWER. THANK YOU AND GOD BLESS

yanalaym [24]

Answer:

System is given below

Step-by-step explanation:

Let (applicable to all three lines below)
Hard candy = x kg with price $1.60/kg
Gummy worms = y kg with price $2.20/kg
Total weight = 50 kg with mixed price $1.75/kg

Required equations:

x + y = 50 total weight
1.60x + 2.20y = 50*1.75 total price

=========================================

Note. It says don't solve but the solution below for those who is interested to know the answer.

Simplify the second equation and solve by substitution x = 50 - y:

1.6(50 - y) + 2.2y = 87.5
80 - 1.6y +2.2y = 87.5
0.6y = 7.5
y = 7.5/0.6
y = 12.5

Find the value of x:

x = 50 - 12.5 = 37.5

Hard candy = 37.5 kg and gummy worms = 12.5 kg

7 0

2 years ago

Find the area of the parallelogram.

Ksivusya [100]

Area=14cm×6cm=84 cm²
..............................

5 0

3 years ago

Read 2 more answers

The quality control manager of a chemical company randomly sampled twenty 100-pound bags of fertilizer to estimate the variance

lisabon 2012 [21]

Answer:

The 95% confidence interval for the variance in the pounds of impurities would be $3.829 \leq \sigma^2 \leq 14.121$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =6.62$ represent the sample variance

s=2.573 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.025,19)" "=CHISQ.INV(0.975,19)". so for this case the critical values are:

$\chi^2_{\alpha/2}=32.852$

$\chi^2_{1- \alpha/2}=8.907$

And replacing into the formula for the interval we got:

$\frac{(19)(6.62)}{32.852} \leq \sigma^2 \frac{(19)(6.62)}{8.907}$

$3.829 \leq \sigma^2 \leq 14.121$

So the 95% confidence interval for the variance in the pounds of impurities would be $3.829 \leq \sigma^2 \leq 14.121$ .

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3 years ago

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Kay [80]

Answer:

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3 years ago