Let a = speed of the plane A, and b = speed of plane B.
(Assume that the net effect of the wind is negligible.)
From the first sentence, the distance between A and B after each travels for 1 hour is a + b miles. From the second sentence, after 45 minutes, or 0.75 hour, the distance between A and B is 200 miles. Plane a has traveled 0.75a, while plane B has traveled 0.75b.
Hence a + b = 0.75a + 0.75b +200
==> 0.25(a + b) = 200.
==> a + b = 800.
Therefore planes A and B are 800 miles apart now.
The second option. A is 36 and B is 20. FD is half of AC, so 18*2 is 36. FB is half of EC, so it’s 20.
Answer: 3080/5280 or (simplified) 7/12
Explanation:
There are 5280 feet in one mile so 3080/5280 is equal to 3080 ft/ 1 mile.
7/12 is equal to 3080/5280 when simplified.
Step-by-step explanation:
6x-12=x+3
6x-x=3+12
5x=15
x=15/5
x=3
