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2 years ago

Which equation represents a line which is parallel to the line 8x + 7y = -28?

Mathematics

1 answer:

Paul [167]2 years ago

5 0

Answer:

-8/7 slope

Step-by-step explanation:

so first u need to figure out the y=mx+b of ur equation 8x+7y=-28 to make it easier on urself yk. so first you get the y by it self and change it to become 7y= -8x-28 you do this by dragging the 8x to the other side which makes it negative since ur switching sides. now u divide each number by 7 since the 7y is by itself. doing this u get y= -8/7x-4. basically parallel = same slope so you will keep ur same slope or m as -8/7 and now all u need to find is b but in ur question u didnt give coordinates so irdk but ur answer has to have the -8/7 slope

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Answer:

[ 60/25 ] x 5 km/h = 12 km/h

Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

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3 years ago

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jenyasd209 [6]

3x + 6y = -24

first you would start by subtracting 3x from both sides which would give you
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then you divide everything by 6 and you’re left with
y = -1/2 - 4

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3 years ago