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Inessa [10]
3 years ago
7

Sumy is working in geometry class and is given figure ABCD in the coordinate plane to reflect. The coordinates of point D are (a

, b) and she reflects the figure over the line y = x. What are the coordinates of the image D'? (a, –b) (b, a) (–a, b) (–b, –a)Sumy is working in geometry class and is given figure ABCD in the coordinate plane to reflect. The coordinates of point D are (a, b) and she reflects the figure over the line y = x. What are the coordinates of the image D'?
(a, –b)
(b, a)
(–a, b)
(–b, –a)
Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0

Answer:

(b, a)

Step-by-step explanation:

Example if D was (3, 2) and reflects across y = x, D' will be (2, 3)

Pie3 years ago
7 0

Answer:

b

Step-by-step explanation:

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The standard deviation of pulse rates of adult males is more than 11 bpm. For the random sample of 153 adult males the pulse rat
Alenkasestr [34]

Answer: 160.4040

Step-by-step explanation:

Here , the claim is "The standard deviation of pulse rates of adult males is more than 11 bpm." , i.e. \sigma>11

We use Chi-square test statistic for the test statistic to test the standard deviations :

\chi^2=\dfrac{(n-1)s^2}{\sigma^2} , where s= sample standard deviation , \sigma = population standard deviations and n = sample size.

As per given , n=153 , s= 11.3

Then, Required test statistic will be :

\chi^2=\dfrac{(153-1)(11.3)^2}{11^2}=\dfrac{152\times127.69}{121}\approx160.4040

Hence, the value of the test statistic. =  160.4040

3 0
3 years ago
Priya is buying raisins and almonds to make trail mix. Almonds cost $5.20 per pound and raisins cost $2.75 per pound. Priya spen
Nostrana [21]

Answer:

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Step-by-step explanation:

4 0
2 years ago
A sample of 8 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop
kenny6666 [7]

Answer:

\bar X= \frac{1.83+1.85+1.79+1.73+1.69+1.74+1.76+1.70}{8}= 1.76125

Now we can estimate the population variance with the sample variance given by:

s^2 = \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

And replacing we got:

s^2 = 0.0033839

And the estimator for the population deviation \sigma is given by :

\hat \sigma = \sqrt{s^2}= \sqrt{0.0033839}= 0.058172

Step-by-step explanation:

For this case we have the following data given:

1.83,1.85,1.79,1.73,1.69,1.74,1.76,1.70

First we need to calculate the mean with the following formula:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X= \frac{1.83+1.85+1.79+1.73+1.69+1.74+1.76+1.70}{8}= 1.76125

Now we can estimate the population variance with the sample variance given by:

s^2 = \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

And replacing we got:

s^2 = 0.0033839

And the estimator for the population deviation \sigma is given by :

\hat \sigma = \sqrt{s^2}= \sqrt{0.0033839}= 0.058172

7 0
4 years ago
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