a formula for the general term a n of the sequence assuming the pattern of the first few terms continues. { − 13/3 , 16/9 , − 19/27 , 22/81 , − 25/243 , ... } is
.
<u>Step-by-step explanation:</u>
Here we have , the pattern of the first few terms continues. { − 13/3 , 16/9 , − 19/27 , 22/81 , − 25/243 , ... } . We need to find a formula for the general term a n of the sequence . Let's find out:
In this question there is no such technique , instead we have to use our brain to manipulate the pattern as :
1st term = − 13/3 = 
2nd term = 16/9 = 
3rd term = − 19/27 = 
4th term = 22/81 = 
5th term = − 25/243 = 
nth term = 
Therefore, a formula for the general term a n of the sequence assuming the pattern of the first few terms continues. { − 13/3 , 16/9 , − 19/27 , 22/81 , − 25/243 , ... } is
.
Answer:
k = 2
Step-by-step explanation:
slope = rise/run = (y1 - y2) / (x1 - x2)
s = (7 - (3-k)) / ((k+3) - (-5)) give slope is 3/5
3/5 = (7 - (3-k)) / ((k+3) - (-5)) then multiply both sides by ((k+3) - (-5))
(3/5)((k+3) - (-5)) = (7 - (3-k))
(3/5)(k+3+5) = 7 - 3 + k
(3/5)(k+8) = 4 + K
3k/5 + 24/5 = 4 + k
3k/5 - k = 4 - 24/5
3k/5 - 5k/5 = 20/5 - 24/5
-2k/5 = -4/5
-2k = -4
k = 2
4a^4 -2b^2 +40
a=2
b=7
4(2)^4 -2(7)^2 +40
PEMDAS is what your gonna use to solve this you go from right to left
First is P which is parentheses which is none
second is E which stands for exponents
4(32)-2(49)+40
now MD multiply or divide
128-98+40
now add or subtract
30+40
last one
70 this is your answer i hope
Answer:
The Answer Is A
Step-by-step explanation: