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EastWind [94]
3 years ago
6

I need help please!!!

Mathematics
1 answer:
Zigmanuir [339]3 years ago
3 0

Answer:

a lot

Step-by-step explanation:

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Suzy is starting a babysitting buisness. She spent $ 36 to make signs to advertise. She charges and intial fee of $ 6 and then $
timofeeve [1]

Answer:

3h - 30 > 0

h > 10

Step-by-step explanation:

To make a profit, subtract $36 in cost from the income coming in.

She charges $6 and then $3 per hour or 3h. Her income coming in is 6 + 3h.

Subtract 36 from it to find the profit.

3h + 6 - 36

3h - 30

To make a profit, she needs to make more than $0 or > 0.

3h - 30 > 0

Solve using inverse operations.

3h - 30 > 0

3h > 30

h > 10

3 0
3 years ago
A house was sold for $300,000 and a profit of 5% was made. Determine its
lara [203]

Answer:

285,000

Step-by-step explanation:

First, you need to figure out how much was profit. Multiply 300k by .05, which should give you 15,000. Then, subtract 15,000 from 300k to get 285k. hope this helps

3 0
3 years ago
Read 2 more answers
in a xy-coordinate system line 1 has a slope of -3. If the points (2,16 and (5,t) are on line 1, what is the value of t?
Dimas [21]
We can use the formula y2-y1/x2-x1 to find our answer. So, we have : t-16/5-2 = -3. We simplify that to t-16/3 = -3. We can then multiply both sides by 3 to get t-16 = -9. Then we can add 16 to both sides to get t = 7.
8 0
3 years ago
What is the value of minus 6 x cubed minus y squared minus 3 x y if if x = -2 and y = 4
Oksi-84 [34.3K]

Well, "minus 6 x cubed minus y squared minus 3 x y" translates to:

-6x^{2} -y^{2} -3xy

Then, if we insert the values for x and y, we get:

-6(-2)^{2} -(4)^{2} -3(-2)(4)

When we distribute and multiply:

144-16-24

And once we combine like terms:

104<em> is the answer</em>


8 0
3 years ago
Read 2 more answers
Actual lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about a mean pregnancy leng
HACTEHA [7]

Solution :

The data is normally distributed.

The standard deviation is 18 days

Here the data is normally distributed and 54 days is 3 days of standard deviation.

Therefore, the percentage of the births that would be \text{expected to occur} within the 54 days of the mean \text{pregnancy} length is given by :

= P( -3 < Z < 3)

= 0.9544

= 95 %

Therefore, about 95% of the births would be \text{expected to occur} within 54 days of the men \text{pregnancy} length.

8 0
3 years ago
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