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3 years ago

10

Find the value of x that makes m ||

1 answer:

marusya05 [52]3 years ago

4 0

3x = 2x + 20
3x - 2x = 20
x = 20

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What is the product of x2+10x+28

Leto [7]

Answer:

40x

Step-by-step explanation:

Add 2, 10, and 28 then it equals 40 and put the x on the side and it equals 40x

7 0

4 years ago

How do i evaluate it????

Kitty [74]

Answer:

1 for all evaluate questions

Step-by-step explanation:

just remember anything to the zero power is 1

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3 years ago

What is the answer for -5a - 12a simplify

USPshnik [31]

-5a - 12a can also be rewritten as:

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4 years ago

Read 2 more answers

Find the area bounded by the given curves: <br> y=2x−x2,y=2x−4

Andrej [43]

Answer:

$A = [\frac{32}{3}]$

Step-by-step explanation:

Given

$y_1 = 2x - x^2$

$y_2 = 2x - 4$

Required

Determine the area bounded by the curves

First, we need to determine their points of intersection

$2x - x^2 = 2x - 4$

Subtract 2x from both sides

$-x^2 = -4$

Multiply through by -1

$x^2 = 4$

Take square root of both sides

$x = 2$ or $x = -2$

This Area is then calculated as thus

$A = \int\limits^a_b {[y_1 - y_2]} \, dx$

<em>Where a = 2 and b = -2</em>

Substitute values for $y_1$ and $y_2$

$A = \int\limits^a_b {(2x - x^2) - (2x - 4)} \, dx$

Open Brackets

$A = \int\limits^a_b {2x - x^2 - 2x + 4} \, dx$

Collect Like Terms

$A = \int\limits^a_b {2x - 2x- x^2 + 4} \, dx$

$A = \int\limits^a_b {- x^2 + 4} \, dx$

Integrate

$A = [-\frac{x^{3}}{3} +4x](2,-2)$

$A = [-\frac{2^{3}}{3} +4(2)] - [-\frac{-2^{3}}{3} +4(-2)]$

$A = [-\frac{8}{3} +8] - [-\frac{-8}{3} -8]$

$A = [\frac{-8+ 24}{3}] - [\frac{8}{3} -8]$

$A = [\frac{-8+ 24}{3}] - [\frac{8-24}{3}]$

$A = [\frac{16}{3}] - [\frac{-16}{3}]$

$A = [\frac{16}{3}] + [\frac{16}{3}]$

$A = [\frac{16 + 16}{3}]$

$A = [\frac{32}{3}]$

Hence, the Area is:

$A = [\frac{32}{3}]$

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4 years ago

Tendons are tissues that connect _____________ to bone.

Leni [432]

Answer:

c). Muscle

tendons are tissues that connect muscles to bone

hope it helps

7 0

3 years ago