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Gnom [1K]
3 years ago
10

A first order reaction has a rate constant of 0.924 at 25 oC. Given that the activation energy is 89.8 kJ/mol, calculate the rat

e constant at 33.3 oC.
Chemistry
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

k_2=2.46

Explanation:

Hello!

In this case, according to the Arrhenius equation for variable temperature:

ln(\frac{k_2}{k_1} )=-\frac{Ea}{R}(\frac{1}{T_2} -\frac{1}{T_1} )

Given the temperatures to be computed in kelvins and the activation energy, we obtain:

ln(\frac{k_2}{0.924} )=-\frac{89800J/mol}{8.314J/(mol*K)}(\frac{1}{306.45K} -\frac{1}{298.15K} )\\\\ln(\frac{k_2}{0.924} )=0.981\\\\k_2=0.924*exp(0.981)\\\\k_2=2.46

Best regards!

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