The correct answer is Sulfur, Arsenic, selenium, silicon, and antimony.
Answer:
4.2 x 10⁴ mL
Explanation:
Data Given:
Density (d) of air = 1.19 x 10⁻³g/mL
Mass of the air (m) = 50 g
Volume of the air (V) = ?
Solution:
Formula will be used
d = m/V
As we have to find volume so rearrange the above equation
V = m/d . . . . . . . . . . . (1)
Put values in above equation 1
V = 50 g / 1.19 x 10⁻³g/mL
V = 4.2 x 10⁴ mL
So,
volume of dry air = 4.2 x 10⁴ mL
During ethyl alcohol fermentation<span>, the pyruvate molecules are broken down into ethyl </span>alcohol<span> molecules and carbon dioxide molecules. During </span>lactic<span> acid</span>fermentation<span>, the pyruvate molecules are broken down into </span>lactic<span> acid molecules only.</span>
Answer: He could add a base to the pool to neutralize the acid.
Explanation:
Chlorine is used to disinfect the pools as it produces hypochlorous acid in water. This hypochlorous acid is unstable and gives hydrochloric acid and nascent oxygen which is used to disinfect.

The excess acid is neutralized by adding base which produces salt and water and thus decrease the acidity.

Adding more acid would increase the acidity further.