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OverLord2011 [107]
3 years ago
8

Solve for x 10x-27. 3x-4

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

= 9.71 Only way I could think of to solve it

Step-by-step explanation:

10x-72=3x-4

7x=68

x=9.71

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5 0
3 years ago
3x+8=15 find try the value of x
dimaraw [331]

Answer:

x = 7/3

Step-by-step explanation:

To find the of x, isolate it from the other numbers (moving everything to the other side)

What you do to one side, you must do to the other:

3x + 8 = 15

3x + 8 - 8 = 15 - 8  (subtract 8 on both sides to rid of the "+ 8")

3x = 7

3x/3 = 7/3   (divide by 3 on both sides to rid of the 3 attached to "x")

x = 7/3

6 0
3 years ago
Read 2 more answers
Yana took a 15-hour flight to Korea he slept for 1/3 of the flight how many minutes did he sleep
Triss [41]
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6 0
3 years ago
There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit
DaniilM [7]

Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = nCr * p^{r} * q^{n-r}

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = 15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}

p(x=3) = 455 * 0.4^{3} * 0.6^{12}

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday  = 1 - 0.0633 = 0.9337

3 0
3 years ago
Wait before you try to answer this i need to put the line on here What is the slope of this line?
PilotLPTM [1.2K]

well, to get the slope of any line, we only need two points, hmmm let's see, from the points there, we can use say, (-4, 5) and (0, 6).


\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{5})\qquad(\stackrel{x_2}{0}~,~\stackrel{y_2}{6})\\\\\\slope = m\implies\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-5}{0-(-4)}\implies \cfrac{6-5}{0+4}\implies \cfrac{1}{4}

8 0
3 years ago
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