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Aloiza [94]
3 years ago
7

Six of 16 students in Mr. McConney's class are serving detentions, the rest are here for tutoring. What percent of students are

here for tutoring?
Mathematics
2 answers:
LuckyWell [14K]3 years ago
5 0

Answer:

63% rounded

Step-by-step explanation:

16-6=10

100/16=6.25

10*6.25=62.5 round to 63%

Ivan3 years ago
3 0

Answer:

62.5%

Step-by-step explanation:

plz mark the brainliest

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A cylinder has a base radius of 7m and a height of 14m. What is its volume in cubic m, to the nearest tenths place?
Westkost [7]

Answer:Answer:

2155.1 m^3

Step-by-step explanation:

area= pi* r ^2 * h =pi * 7^2 *14 = 2155.1 m^3

6 0
2 years ago
Find the volume for #3 THANKSSSSSSSSSS
tresset_1 [31]
The volume of number three is 63.7
6 0
3 years ago
3. Jenny puts two wooden blocks together. One block has a length of 5 in., a width of 4 in., and a
Mazyrski [523]

Answer:

140 inches cubed

Step-by-step explanation:

Use the formula V = length * width * height to find the volumes of each block, then add them together to get the combined volume. So, (5 * 4 * 5) + (4 * 5 * 2) = 140 inches cubed, which is the combined volume.

Hopefully this helps- let me know if you have any questions!

3 0
2 years ago
H. C. F of 20,40 and 50​
Vesnalui [34]

Answer:

10

Step-by-step explanation:

HCF of 20, 40 & 50:

20: 1, 2, 4, 5, 10, 20

40: 1, 2, 4, 5, 8, 10, 20, 40

50: 1, 2, 5, 10, 25, 50

HCF: 10

Topic: HCF and LCM

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks!

8 0
2 years ago
What is the relationship between the ratios?
Naily [24]

Given:

\dfrac{10}{24} and \dfrac{5}{12}.

To find:

The relationship between the ratios.

Solution:

We have, two ratios in the fraction form.

\dfrac{10}{24} and \dfrac{5}{12}

First ratio = \dfrac{10}{24}

                = \dfrac{2\times 5}{2\times 12}

                =\dfrac{5}{12}           (Cancel out the common factors)

First ratio = Second ratio

Since, the both ratios are equal to each other, therefore, the given ratios are equivalent ratios.

5 0
3 years ago
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