Answer:
Step-by-step explanation:
REcall the following definition of induced operation.
Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.
So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.
For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).
Case SL2(R):
Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So
.
So AB is also in SL2(R).
Case GL2(R):
Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So
.
So AB is also in GL2(R).
With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).
Given:
The inequality is

To find:
The inequality that solution describes all the solutions to the given inequality.
Solution:
We have,

Using distributive property, we get




Divide both sides by 3.


It can be written as

Therefore, the value of x is greater than 3. So, the required inequality is either
or
.
11+b-y
Hope this helps
Have a happy holidays
A=B H
area equals the base times the height
Answer:
7.2 km
Step-by-step explanation:
Distance between Brookfield to Seaside = 20.4 km
Distance between Yardley and Seaside = 13.2 km
Let distance between Brookfield to Yardley be x.
Thus:
x + 13.2 km = 20.4 km
Subtract 13.2 from each side
x = 20.4 - 13.2
x = 7.2
Distance from Brookfield to Yardley is 7.2 km