No one see the quadrilateral
<h3>The solution is (x, y) = (3, -24)</h3>
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-3x - y = 15 -------- eqn 1
y = -8x ------ eqn 2
We have to find solution of (x, y)
We can solve by substitution method
<em><u>Substitute eqn 2 in eqn 1</u></em>
-3x - (-8x) = 15
-3x + 8x = 15
5x = 15
Divide both sides by 5
<h3>x = 3</h3>
Substitute x = 3 in eqn 2
y = -8(3)
<h3>y = -24</h3>
Thus solution is (x, y) = (3, -24)
Answer:
See below, :)
Step-by-step explanation:
Hello!
From the exterior angle theorem, we know that an exterior angle is equal to remote interior angles added up. The exterior angle in this problem is 140 degrees so we also know that the remote interior angles are congruent. We can denote the interior angles as x and both combined is 2x.
Then we can create the equation:
2x = 140
x = 70
The two remote interior angles are 70 degrees.
The last interior angle is 180 - 140 = 40 degrees
Answer:
V(x,y,z) ≈ 61.2 in
Step-by-step explanation:
for the function f
f(X)=x³
then the volume will be
V(x,y,z)= f(X+h) - f(X) , where h= 0.2 (thickness)
doing a Taylor series approximation to f(x+h) from f(x)
f(X+h) - f(X) = ∑fⁿ(X)*(X-h)ⁿ/n!
that can be approximated through the first term and second
f(X+h) - f(X) ≈ f'(x)*(-h)+f''(x)*(-h)²/2 = 3*x²*(-h)+6*x*(-h)²/2
since x=L=10 in (cube)
f(X+h) - f(X) ≈ 3*x²*(-h)+6*x*(-h)²/2 = 3*L²*h+6*L*h²/2 = 3*L*h*(h+L)
then
f(X+h) - f(X) ≈ 3*L*h*(h+L) = 3* 10 in * 0.2 in * ( 0.2 in + 10 in ) = 61.2 in
then
V(x,y,z) ≈ 61.2 in
V real = (10.2 in)³-(10 in)³ = 61 in
<u>Answer:</u>
Graph 2
<u>Step-by-step explanation:</u>
We are given the following compound inequalities and we are to find its solution and then determine whether which of the graphs correctly shows it"
or 
Therefore, graph 2 shows it correctly.
