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2 years ago

The area of a trapezoid is 60 square feet. If the bases of the trapezoid are 8 feet and 12 feet, what is the height?

Mathematics

1 answer:

Margarita [4]2 years ago

7 0

Answer:

Step-by-step explanation:

60 = 12+8 divided 2 times height

60 = 20/2 x H

60 = 10 x H

60/10 = h

6 = H

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What is the answer to this question because i do not know 5/12 x =1

Otrada [13]

Answer:

x=12/5

Step-by-step explanation:

x*5/12=1

x=1*12/5

x=12/5

3 0

1 year ago

Read 2 more answers

How do combine like terms 3x plus 3y minus 5x minus y?

miskamm [114]

3x+3y-5x-y

(3x-5x) +(3y-y)

(3-5)x + (3-1)y

-2x+2y

4 0

2 years ago

1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t

Sophie [7]

$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

$\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}$

So after 70 days, 5.625 mg will be left

4 0

10 months ago

Find the value of x. Thank YOU.

atroni [7]

Answer:

x=22

Step-by-step explanation:

180-48=132

360-132=228

25+85+228=338

360-338=22

3 0

2 years ago

Read 2 more answers

A fire department's ladder is 110 feet long. A firefighter is trying to reach the top of a 100 foot building by leaning the ladd

Alekssandra [29.7K]

Answer:

sin-¹(10/11)

Step-by-step explanation:

The height of the building is 100 ft and the ladder is 110ft long .We can imagine this situation as a right angled ∆. For figure refer to the attachment .

We can use ratio sine here. Let the angle of elevation be theta.

In ∆ ABC :-

=> sinθ = p/h

=> sinθ = 100ft / 110 ft

=> sinθ = 10/11

=> θ = sin -¹ ( 10/11) .

<h3>Hence the angle of elevation is sin -¹ ( 10/11). </h3>

6 0

2 years ago