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JulijaS [17]
3 years ago
9

Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added toge

ther, the x term is eliminated? 1 5 3 4 TY - y = 8 0-10 times the first equation and 3 times the second equation O 10 times the first equation and 3 times the second equation 0 -3 times the first equation and 5 times the second equation O 3 times the first equation and 5 times the second equation​

Mathematics
1 answer:
Anna11 [10]3 years ago
3 0

Answer:

The correct answer is A.

Step-by-step explanation:

1/5*-10/1=-10/5= -2

2/3*3/1=6/3=      2

----------------------------

                          0.

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Two candidates ran for class president. The candidate that won received 70% of the 350 total votes. How many votes did the winni
labwork [276]

Answer:

49 votes

Step-by-step explanation:

Because 70% of the 350 is 49

3 0
3 years ago
Which expression is equivalent to -8(10x-3)<br> (SHOW WORK)
oksian1 [2.3K]

Answer:

240

Step-by-step explanation:

-8(10×-3)

(10×3)=30

30×-8=240

4 0
3 years ago
Give two examples of line segments that will make a triangle ?
77julia77 [94]

Answer:

If the length of any one side is greater than the sum of the length of the other two, the line segments cannot be used to create a triangle. It is possible to create a triangle using 3 line segments if the sum of the lengths of any two line segments is greater than the length of the third.

7 0
3 years ago
Help asap please i don't know the answer lol
Sveta_85 [38]

Answer:

H

Step-by-step explanation:

The parallel line BC divides the sides AD and AE in proportion, that is

\frac{AB}{BD} = \frac{AC}{CE}, that is

\frac{2}{3} = \frac{AC}{4} ( cross- multiply )

3AC = 8 ( divide both sides by 3 )

AC = \frac{8}{3} = 2 \frac{2}{3}, hence

AE = AC + CE

     = 2 \frac{2}{3} + 4 = 6 \frac{2}{3} → H

6 0
4 years ago
Help me i’m stressed
Aleks04 [339]

Answer:

<h3>m∠1 = 41°</h3><h3>m∠2 = 41°</h3>

Step-by-step explanation:

<h3>m∠1 = m∠2</h3>

{(6x + 11)}^{o}   =  {(10x - 9)}^{o}  \\ 11 + 9 = 10x - 6x \\ 20 = 4x \\  \frac{20}{4}  =  \frac{4x}{4}  \\ 5 = x \\

x = 5°,

m∠1 = (6x + 11)°

{(6x  + 11)}^{o}  \\ 6(5) + 11 \\ 30 + 11 \\  {41}^{o}  \\

5 0
3 years ago
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