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2 years ago

Figure a has 1/3 of its hole shadded enter another fraction equal to 1/3 ASAP 20 PONITS ON THE LINE

Mathematics

1 answer:

Mashutka [201]2 years ago

3 0

Answer:

It would be 4/12 or 2/6

Step-by-step explanation:

4÷ 12 = 3 = 1/3 and 2÷6 = 3 =1/3

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If a is the set of all integers choose the set B that will make the following statement false

Tju [1.3M]

Answer:

Try the 2nd one

Step-by-step explanation:

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3 years ago

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Erry has taken a random sample of students and determined the number of electives that each student in his sample took last year

Cerrena [4.2K]

The mean should be about the same, because the sample is random

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3 years ago

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(1)/(2)(8y-4)=(3)/(4)(16-8y)

Talja [164]

Answer: y=7/5

Hope this helps

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3 years ago

“encontrar la integral indefinida y verificar el resultado mediante derivación”

Oliga [24]

$I=\displaystyle\int\frac x{(1-x^2)^3}\,\mathrm dx$

Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{y^3}=\frac1{4y^2}+C=\frac1{4(1-x^2)^2}+C$

Para confirmar el resultado:

$\dfrac{\mathrm dI}{\mathrm dx}=\dfrac14\left(-\dfrac{2(-2x)}{(1-x^2)^3}\right)=\dfrac x{(1-x^2)^3}$

$I=\displaystyle\int\frac{x^2}{(1+x^3)^2}\,\mathrm dx$

Sustituye:

$y=1+x^3\implies\mathrm dy=3x^2\,\mathrm dx$

$\implies I=\displaystyle\frac13\int\frac{\mathrm dy}{y^2}=-\frac1{3y}+C=-\frac1{3(1+x^3)}+C$

(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

$I=\displaystyle\int\left(1+\frac1t\right)^3\frac{\mathrm dt}{t^2}$

Sustituye:

$u=1+\dfrac1t\implies\mathrm du=-\dfrac{\mathrm dt}{t^2}$

$\implies I=-\displaystyle\int u^3\,\mathrm du=-\frac{u^4}4+C=-\frac{\left(1+\frac1t\right)^4}4+C$

Podemos hacer que esto se vea un poco mejor:

$\left(1+\dfrac1t\right)^4=\left(\dfrac{t+1}t\right)^4=\dfrac{(t+1)^4}{t^4}$

$\implies I=-\dfrac{(t+1)^4}{4t^4}+C$

4 0

3 years ago

Dominos.com allows you to build your own pizza online, but it only reveals the price at the end of the process. Watch

Ede4ka [16]

Answer:

Hi there!

Your answer is:

Domino's waits to reveal the price until the end because, psychologically, you're predisposed to put & LEAVE more toppings on your pizza. If you see how each topping affects the price of the pizza each time you add one, you may limit the amount you choose. If you wait until the end to see it, by that point you think "Well I <em>need</em> these toppings on there to make it delicious." From a business standpoint, it's more financially beneficial to use the "hide the price until the end" system. However, from a consumer standpoint, most prefer seeing a live breakdown of how each topping affects the price so we can limit what we pay to a reasonable amount.

I hope this helps!

3 0

3 years ago