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2 years ago

Which graph is proportional ????

Mathematics

2 answers:

Vikentia [17]2 years ago

5 0

I would say bottom left.

pav-90 [236]2 years ago

3 0

Answer: "The graph in the UPPER, LEFT-HAND CORNER."
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PLSS helpppppppppppppp like plssss

Minchanka [31]

Answer:

f=21-16, 5

Step-by-step explanation:

Just subtract 16 from both sides to get 5 as the solution

7 0

2 years ago

Read 2 more answers

What is the probability of rolling a sum of 8 on a standard pair of six-sided dice? express your answer as a fraction or a decim

maxonik [38]

First lets see how many combinations there are that make 8 from the numbers 1-6:

2+6
3+5
4+4
5+3
and 6+2.

Note: the order does matter, because you roll two die. This means the first die has a number and the second die also has a number. 2 on 1st dice and 6 on 2nd dice would be a different combination than 2 on 2nd dice and 6 on 1st dice.

Now we calculate the probability of getting a number 2 through 6 on the first dice: which is 5/6.

Then calculate the probability of getting a number that pairs up with the first number to make 8: *Note: once you get a number 2 through 6, there is only one other number that you can roll to make 8. This means the probability of getting a match would be 1/6 on the 2nd dice.

Finally, multiply the two fractions we got earlier: 5/6 x 1/6 = 5/36

Your probability would be 5/36 in fraction form, 13.89% in percent form, or 0.139 in decimal form rounded 3 places.

Hope this helps, and May the Force Be With You!

-Jabba the Hut

7 0

3 years ago

Please help solve by elimination I hope its not blurry Have a nice day and Goodnight

strojnjashka [21]

Answer:

$\displaystyle \textcolor{black}{4.}\:[-3, -5]$

$\displaystyle \textcolor{black}{3.}\:[8, -1]$

$\displaystyle \textcolor{black}{2.}\:[4, -7]$

$\displaystyle \textcolor{black}{1.}\:[3, -2]$

Step-by-step explanation:

When using the Elimination method, you eradicate one pair of variables so they are set to zero. It does not matter which pair is selected:

$\displaystyle \left \{ {{2x - 3y = 9} \atop {-5x - 3y = 30}} \right.$

{2x - 3y = 9

{⅖[−5x - 3y = 30]

$\displaystyle \left \{ {{2x - 3y = 9} \atop {-2x - 1\frac{1}{5}y = 12}} \right. \\ \\ \frac{-4\frac{1}{5}y}{-4\frac{1}{5}} = \frac{21}{-4\frac{1}{5}} \\ \\ \boxed{y = -5, x = -3}$

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$\displaystyle \left \{ {{x - 2y = 10} \atop {x + 3y = 5}} \right.$

{x - 2y = 10

{⅔[x + 3y = 5]

$\displaystyle \left \{ {{x - 2y = 10} \atop {\frac{2}{3}x + 2y = 3\frac{1}{3}}} \right. \\ \\ \frac{1\frac{2}{3}x}{1\frac{2}{3}} = \frac{13\frac{1}{3}}{1\frac{2}{3}} \\ \\ \boxed{x = 8, y = -1}$

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$\displaystyle \left \{ {{y = -3x + 5} \atop {y = -8x + 25}} \right.$

{y = −3x + 5

{−⅜[y = −8x + 25]

$\displaystyle \left \{ {{y = -3x + 5} \atop {-\frac{3}{8}y = 3x - 9\frac{3}{8}}} \right. \\ \\ \frac{\frac{5}{8}y}{\frac{5}{8}} = \frac{-4\frac{3}{8}}{\frac{5}{8}} \\ \\ \boxed{y = -7, x = 4}$

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$\displaystyle \left \{ {{y = -x + 1} \atop {y = 4x - 14}} \right.$

{y = −x + 1

{¼[y = 4x - 14]

$\displaystyle \left \{ {{y = -x + 1} \atop {\frac{1}{4}y = x - 3\frac{1}{2}}} \right. \\ \\ \frac{1\frac{1}{4}y}{1\frac{1}{4}} = \frac{-2\frac{1}{2}}{1\frac{1}{4}} \\ \\ \boxed{y = -2, x = 3}$