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solniwko [45]
3 years ago
8

Which graph is proportional ????

Mathematics
2 answers:
Vikentia [17]3 years ago
5 0
I would say bottom left.
pav-90 [236]3 years ago
3 0
Answer:  "The graph in the UPPER, LEFT-HAND CORNER."
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Please I need help quick
mafiozo [28]
The ratios are both identical

sin x = perpendicular/hypotenuse = 3/5
cosy = base/hypotenuse = 3/5
4 0
3 years ago
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PLZ HELP PLZ! TY! WILL GIVE BRAINLIEST TO WHOEVER ANSWERS
Marysya12 [62]
Take the y and x and 4 as a common factor and you will get 4xy(2yz+3x) the second one is the answer
7 0
4 years ago
A cone and cylinder have the same height and their bases are congruent circles. If the volume of the cylinder is 120 cubic inche
NikAS [45]

Answer:

Volume of cone = 40 in³

Step-by-step explanation:

Given:

Volume of cylinder = 120 in³

Height of cylinder = Height of cone

Radius of cylinder = Radius of cone

Find:

Volume of cone

Computation:

Volume of cylinder = πr²h = 120 in³

Volume of cone = (1/3)πr²h

So,

Volume of cone = (1/3)(120)

Volume of cone = 40 in³

3 0
4 years ago
What is the length of segment TQ.
Jobisdone [24]

Answer:

C )  14 units

Step-by-step explanation:

I am assuming this is the problem's image? If not, please let me know and I will do a different one. I hope this helps!

We know QV = 15 and TQ = TS, QV = SV;

4 x - 1 = 15

4 x = 15 + 1

4 x = 16

x = 16 : 4 = 4

so,

TQ = 3 * 4 + 2 = 12 + 2 = 14

Answer:

C )  14 units

3 0
3 years ago
The costs of different weights of onions sold at a grocery store are shown in the table
lana66690 [7]

Answer:

<h2>Independent variable: Weight of Onions.</h2><h2>Dependent variable: Total Cost.</h2>

Step-by-step explanation:

The given table is about the weight of onions in pounds and the total cost.

If you think this through, you would notice that the total cost depends on the number of pounds of onions. That means the independent variable is Weight of Onions and the dependent variable is the Total Cost.

So, to put it in a sentence: The weight of onions determines the total cost.

8 0
3 years ago
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