*im sorry but I cant see the bottom number but I'll consider it as x
tan 45° = 3/x
x = 3/tan45
x is 3
hope this helps :)
<span>y= 2x ^2 - 8x +9
</span>y = a(x - h)2 + k, where (h, k) is the vertex<span> of the parabola
</span>so
y= 2x ^2 - 8x + 9
y= 2x ^2 - 8x + 8 + 1
y = 2(x^2 - 4x - 4) + 1
y = 2(x - 2)^2 + 1 ....<---------<span>vertex form</span>
Answer:
And on this case we can use the product rule for a derivate given by:
Where and
And replacing we have this:
Step-by-step explanation:
We assume that the function of interest is:
And on this case we can use the product rule for a derivate given by:
Where and
And replacing we have this:
Step-by-step explanation:
can't really use the Pythagorean because you don't know this is a right triangle.
use the fact that they are similar
so
3/6 = x/12 where x is FE
cross multiply
6x = 36 therefore FE = 6
then 6/12 = y/9 where y is FD
cross multiply
12y = 54 = 54/12 therefore FD = 4.5