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Elena-2011 [213]
3 years ago
11

NEED HELP ASAP

Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0

Step-by-step explanation:

x' = ⅓ x => x = 3x'

f'(x) = 7(3x')+1

= 21x' + 1

so g(x) = 21x + 1

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4/x - x^2 and 3.9x^3-4.1x^2+7.3
7 0
3 years ago
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7th grade math plz help
mina [271]

Answer:

x = 3

y = 3/2

Step-by-step explanation:

look at the hangers to form an equation:

x + x + x + 3 + 3 + 3 = x + x + y + y + y + y

simplify

3x + 3 = 2x + 4y

x + 3 = 4y

x = 4y - 3

you also know that

x + x = y + y + y + y

2x = 4y

substitute x = 4y - 3 into this equation ^

2x = 4y

2(4y - 3) = 4y

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4y = 6

y = 6/4

y = 3/2

2x = 4y

2x = 12/2

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7 0
3 years ago
G(r)=-1-7r <br>g(6)=?<br><br>does anyone know the answer to this?
Lesechka [4]

So for this, replace the r variable in the equation with 6 to solve:

g(6)=-1-7*6\\ g(6)=-1-42\\ g(6)=-43

7 0
3 years ago
Help I thought I had it but i don’t
Mariana [72]

Oops wrong one man I’m sorry

7 0
4 years ago
HH represents the height of the tree (in centimeters), t tt years since Renata moved in. H = 210 + 33 t H=210+33tH, equals, 210,
Jet001 [13]

Answer:

Therefore the rate of growth of the tree is 33 cm/ yr.

Step-by-step explanation:

Given that,

The height of the tree is

H= 210 +33t

Here H represent the height of tree in cm and t is time in year.

The rate of growth is the first order derivative of the H with respect to time.

i.e The rate of growth  =\frac{dH}{dt}

∴H= 210 +33t

Differentiating with respect to t

\frac{dH}{dt} =0 +33

\Rightarrow \frac{dH}{dt}=33

Therefore the rate of growth of the tree is 33 cm/ yr.

7 0
3 years ago
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