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Dvinal [7]
2 years ago
10

If the circumference of a circle is 21 inches, what is the diameter? Use 3.14 for and round your answer to the nearest hundredth

.
Mathematics
1 answer:
Ket [755]2 years ago
7 0
You would divide 21 by 3.14

Which would give you 6.687 now round up to the nearest hundredth
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A box contains four equal-sized cards labeled 1 , 3, 5, and 7. Tim will select one card from the box. What is the probability th
JulsSmile [24]

Answer: 1/4

Step-by-step explanation:

Since the box box contains four equal-sized cards labeled 1 , 3, 5, and 7. The probability of selecting any number out of the four numbers will be 1/4 if they are selected once.

If Tim selects one card from the box, the probability that Tim will select a card labeled 3 will be: = 1/4

This is because 3 only occurs once and there are 4 numbers in total.

7 0
2 years ago
The perimeter of this triangle is 25 units. An angle bisector divides one side of the triangle into lengths of 2 and 3. Find the
grin007 [14]

Answer:

   8 and 12

Step-by-step explanation:

Sides on one side of the angle bisector are proportional to those on the other side. In the attached figure, that means

  AC/AB = CD/BD = 2/3

The perimeter is the sum of the side lengths, so is ...

  25 = AB + BC + AC

  25 = AB + 5 + (2/3)AB . . . . . . substituting AC = 2/3·AB. BC = 2+3 = 5.

  20 = 5/3·AB

  12 = AB

  AC = 2/3·12 = 8

_____

<em>Alternate solution</em>

The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.

That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).

Likewise, 3 of the 15 units are in the segment being divided (BD), so the other 12 units are in that side of the triangle (AB).

The remaining sides of the triangle are AB=12 and AC=8.

7 0
3 years ago
Need help plsss<br> Question is below
tatuchka [14]

Answer:

Step-by-step ex

its 0.2

5 0
3 years ago
The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
Gala2k [10]

We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: (2w+33)^2=w^2+(2w+31)^2. Distributing by multiplying we simplify to 4w^2+132w+1089=w^2+4w^2+124w+961. We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have w^2-8w-128=0. The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!

8 0
3 years ago
If f(x)=4x-20 what is f(4)
Rudik [331]

Answer:

<h2>f(4) = -4</h2>

Step-by-step explanation:

f(x) = 4x - 20

f(4) → put x = 4 to the equation of the function:

f(4) = 4(4) - 20 = 16 - 20 = -4

3 0
3 years ago
Read 2 more answers
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