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bogdanovich [222]
3 years ago
11

Will give brainlist! need the answer thanks!!!

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

2A+3B=\begin{bmatrix}-12&21\\14&-19\end{bmatrix}

Step-by-step explanation:

A=\begin{bmatrix}3&6\\1&4\end{bmatrix} B=\begin{bmatrix}-6&3\\4&-9\end{bmatrix}

2A=2\begin{bmatrix}3&6\\1&4\end{bmatrix} 3B=3\begin{bmatrix}-6&3\\4&-9\end{bmatrix}

2A=\begin{bmatrix}6&12\\2&8\end{bmatrix} 3B=\begin{bmatrix}-18&9\\12&-27\end{bmatrix}

2A+3B=\begin{bmatrix}  6&12\\2&8\end{bmatrix}+\begin{bmatrix}-18&9\\12&-27\end{bmatrix}

2A+3B=\begin{bmatrix}  6+(-18)&12+9\\2+12&8+(-27)\end{bmatrix}

2A+3B=\begin{bmatrix}6-18&12+9\\2+12&8-27\end{bmatrix}

\huge\purple{2A+3B=\begin{bmatrix}-12&21\\14&-19\end{bmatrix}}

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5 0
3 years ago
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Write the quadratic function in vertex form: f(x) = 4x2 + 2x -5
Andrei [34K]
Please use " ^ " to denote exponentiation:  <span>f(x) = 4x^2 + 2x -5.  To find the vertex form of this equation, complete the square:

f(x) = 4x^2 + 2x                                           - 5
      = 4(x^2 + (2/4)x)                                         - 5
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3 0
3 years ago
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Solve this pls. WILL AWARD BRAINLIEST TO BEST ANSWER!!!!!
telo118 [61]

Answer: 31.18

Step-by-step explanation:

The problem is focused on mainly the right triangle made up of points M, Q, and R.  This problem can be solved with the base formula, <em>b</em> = <em>a</em> · tan(β) where <em>a</em> = the length of line MR, β = m∠MQR, and <em>b</em> is the unknown length of RQ.  

Given:

RQ = 18 · tan(60°)

Point M is the midpoint of line PM and line MR.  Since MP is equal to 18, MR has to be 18 as well.  This means that the value of <em>a</em> is 18.

The vertex of ∠MQR is Q, which is 60°.

Step 1: Find the tangent of 60°

The tangent of 60° is √3

Step 2: Solve

RQ = 18 · √3

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4 0
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Viefleur [7K]

Answer:

B would be -7

Step-by-step explanation:

Because 6 times -7 equals -42

4 0
3 years ago
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