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Len [333]
3 years ago
7

Which graph shows the solution set for Negative 1.1 x + 6.4 greater-than negative 1.3? A number line going from negative 10 to 0

. An open circle is at negative 7. Everything to the left of the circle is shaded. A number line going from negative 10 to 0. An open circle is at negative 7. Everything to the right of the circle is shaded. A number line going from 0 to 10. An open circle is at 7. Everything to the left of the circle is shaded. A number line going from 0 to 10. An open circle is at 7. Everything to the right of the circle is shaded.
Mathematics
2 answers:
konstantin123 [22]3 years ago
8 0

Answer:

its c

Step-by-step explanation:

took exam

Rufina [12.5K]3 years ago
4 0

Answer:

A number line going from 0 to 10. An open circle is at 7. Everything to the left of the circle is shaded.

Step-by-step explanation:

We have the following inequality:

-1.1x + 6.4 > -1.3

to solve it, we need to isolate x, as follows:

-1.1x > -1.3 - 6.4

-1.1x > -7.7

x < -7.7/-1.1     (notice that while dividing with a negative number, the sign          changes)

x < 7

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kiruha [24]
If there are 6 friends and half as many food bars as friends, then each friend would get half a food bar. How that each of the 3 food bars are split in half, there is 6 pieces for the 6 friends! :)
6 0
3 years ago
Find the distance between the points given. (0,5) and (-5,0)
galina1969 [7]

Answer:

5\sqrt{2}

Step-by-step explanation:

Calculate the distance between the points using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (- 5, 0)

d = \sqrt{(-5-0)^2+(0-5)^2}

  = \sqrt{(-5)^2+(-5)^2}

  = \sqrt{25+25} = \sqrt{50} = 5\sqrt{2} ← exact value

5 0
3 years ago
Solve using elimination x-2y=12 and 5x+3y=-44 <br> (4,8)<br> (-4,8)<br> (4,-8)<br> (-4,-8)
Leya [2.2K]

Answer:

(-4, -8)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

x - 2y = 12

5x + 3y = -44

<u>Step 2: Rewrite Systems</u>

x - 2y = 12

  1. [Multiplication Property of Equality] Multiply everything by -5:                  -5x + 10y = -60

<u>Step 3: Redefine Systems</u>

-5x + 10y = -60

5x + 3y = -44

<u>Step 4: Solve for </u><em><u>y</u></em>

<em>Elimination</em>

  1. Combine 2 equations:                                                                                   13y = -104
  2. [Division Property of Equality] Divide 13 on both sides:                              y = -8

<u>Step 5: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x - 2y = 12
  2. Substitute in <em>y</em>:                                                                                                x - 2(-8) = 12
  3. Multiply:                                                                                                           x + 16 = 12
  4. [Subtraction Property of Equality] Subtract 16 on both sides:                      x = -4
6 0
3 years ago
What is 1 2/3 as an improper fraction
prohojiy [21]
1 2/3 is 5/3 as in improper fraction
5 0
3 years ago
Read 2 more answers
The endpoints of GH are G(3,3) and H(-7,7).<br> Find the coordinates of the midpoint M.
sesenic [268]

Step-by-step explanation:

Hey there!!

You can simply use midpoint formulae to find midpoint of the coordinates.

Here, Given that;

G(3,3) and H(-7,7).

Using midpoint formulae,

midpoint \: of \: gh =  (\frac{x1 + x2}{2}  ,\frac{y1 + y2}{2})

midpoint \: of \: gh =  (\frac{3 - 7}{2}  ,\frac{3 + 7}{2})

After simplifying it we get,

= (-2,5).

Therefore, midpoint of GH is M(-2,5).

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
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